Solve equation 2 root number X 2 1 root number X 2 2X 2 root number X 2 2X 10

Root number (x 2+1) = root number [(x-0) 2+(0-1) 2], which represents the distance from point (x,0) to (0,1);

Let vector a=(0,1)-(x,0)=(-x,1).

Root number (x 2-2x+2) = root number [(x-1) 2+1] = root number [(x-1) 2+(0-1) 2], which indicates the distance from point (x,0) to (1,1);

Let vector b = (1,1)-(x,0) = (1-x,1).

Root number (x 2+2x+10) = root number [(x+1) 2+9] = root number [(x+1) 2+(0-3) 2], which indicates the distance from point (x,0) to (-1,3);

Let vector c = (-1,3)-(x,0)=(-1-x,3).

where the symmetry of the point (1,1) with respect to the x-axis (1,-1) is exactly on the extension of the remaining two points (-1,3) and (0,1), so that the vector b'=(1,-1)-(x,0)=(1-x,-1), then |b'|=|b|.

Note the vector a, vector b', the relationship between the second value of vector c:

1-2 (-1)=3, then, it is necessary to satisfy the vector a-2 vector b'= vector c

i.e. (-x,1)-2(1-x,-1)=(-1-x,3).

So, -x-2(1-x)=-1-x

The solution is x=1 2

The original equation can become.

x+2 (x(x+2))+x+2)+[x+ (x+2)]-6=0 x+ (x+2)] 2+[ x+ (x+2)]-6=0 req x+ (x+2)=t

t^2+t-6=0

T = 2 or -3

t=-3 is not possible to disperse, so it is discarded.

x=1 4

Therefore, x=1 4 is the search for the socks that are flushed.

x 2-2 scrambled pants number: 2x=-1

x 2-2 root number 2x+2=1

x-Gen Li Zheng No. Heng Song 2) square = 1

x1 = root number 2-1

x2 = root number 2 + 1

x=(-b±√(b^2-4ac))/2a

x=[(2 2 (8-8)] 2*2)= 2 2 The root of the equation is x1=x2= 2 2

It is recommended to use the perfect flat method to solve this problem in the future, namely:

2x-1) ( 2x-1)=0,x1=x2= 2 2 Note that the answer to this question should not be written as x= 2 2, which is incorrect in the sense of strict suspicion].

The formula can be obtained (root number x + root number (x+2) + 3) * (root number x + root number (x+2)-2) = 0 before Evergrande is 0, which is calculated: root number x + root number (x + 2) - 2 = 0

The title "root number (x2+2x)" is not clear, can you change the title more beautifully??? Especially the data in parentheses).

1 + root number 2) x 2 - (3 + root number 2) x 2 + root number 2 = 0, simplification -2x 2 + root number 2 = 0, x = + plus or minus four root number 2 root number 2.

1 + root number 2) x 2 - (3 + root number 2) x + root number 2 = 0 factorization, [(1 + root number 2) x-1] [(1 + root number 2) x - root number 2] = 0. So x1 = root number 2-1; x2 = root number 2

Did you make a mistake in the title? The second item should be a one-time of x, right, so that the factorization ability can be examined. The answers are root number 2 and follow number 2 minus 1 respectively. Right? That's plus or minus 2 -1 4

1 + root number 2) x 2 - (3 + root number 2) x 2 + root number 2 = 0 factorization yields:

1 + root number 2) x-1][x - root number 2] = 0

So, x1 = root number 2

x2=1 (root number 2+1) = root number 2-1

Merge the same kind of items you will, first remove the brackets, put the root number 2 x 2 together. It's easy to solve.

2*x 2=-root number 2

x 2 = root number 2 2