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2x+2y=1 ①
6x-6y=1 ②
Multiply by 3 to get:
6x+6y=3, get: 12x=4
x=1 3 is given by y=(1-2x) 2=1 6so. x=1/3
y=1/6
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Multiply the first equation by 3, and then add it with the second equation to get 12x=4, x=1 3, and then substitute the first equation to get y=1 6That's it.
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From 2x 2y=1 we get 6x 6y=3
Then from the question 6x-6y=1
6x 6y 6x-6y=3 1
So 12x=4 x=1 3
From 2x 2y=1 we get y=1 6
In summary, x=1 3
y=1/6
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2(x+y)=1 6(x-y)=1
x+y) = 1/2 x-y = 1/6
x+y) + (x-y) = 1/2 + 12/6 x = 2/3
x = one-third.
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Question 1: x-3y=2(1)
2x+6y=5.(2)
From (1), x=3y+2
Substitution (2), get.
2(3y+2)+6y=5
There is no solution to this equation with the Lu Sui group!
The second stupid divination question: x-3y=2(1)
2x+6y=-4.(2)
From (1), x=3y+2
Substitution (2), get.
2(3y+2)+6y=-4
y is any number of the foci.
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3x+2y=7 ①
6x-2y=-1 ②
9x=6x=2 Brother digs 3
Substitution for Jingyou y=
The solution of the system of equations is.
x=2/3y=
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From 2 nuclear world 3x+5 6y=1, x=3 2-5 4y substituting x=3 2-5 4y into 1 3x+1 6y=-1, solving y=6 and substituting y=6 into x=3 2-5 4y, solving x=-6, so change the reed limb.
x=-6,y=6
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2x+3y=6(a)
3x-2y=-2(b)
a)*2, 4x+6y=12(c).
b)*3, 9x-6y=-6(d).
c) + (d), to get 13x=6, x=6 13, to substitute x=6 13 into blind (a), to get 2*6 13+3y=6
y=22/13
The hidden object is x=6 13,y=22 and 13
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y=2-2 3*x is a straight line, 10, because 2x+3y=1, so 3y=1-2x, then y must be odd;
and 2x+3y=6, so 3y=2(3-x), the source cong friend y must be even;
Therefore, there is no solution to meet the meaning of the hail locust. ,2,x=-1y1 What does it mean, I don't understand it! ,2,x=-6-3t
t is an integer) y=6+2t,1, if Zheng Zao's equation 2x+3y=1, there is a set of solutions as (x=-1y1), and the general solution of the equation 2x+3y=6 is .
x=-1,y=1
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x-2y=5
So the loss is early x = 2y + 5
Replace the old car into the car airlift 2x+7y=-1
4y+10+7y=-1
11y=-11
So. y=-1
x=2y+5=3
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①2x+2y=1,②6x—6y=1;
Simplification: x+y=1 2, x-y=1 6;
Reel + 2x=4 6=2 3 x=1 3;
Bring in : 1 3 + y = 1 2 y = 1 6 so: x = 1 3, y = 1 6.
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Obtained from 2x 2y 1.
6x 6y 3 in one.
6x 6y 1 two-type.
It is obtained by adding one formula to two.
12x=4x=1/3
Substitute two formulas, get.
6x1/3-6y=1
2-6y=1
6y=1-2
6y=-1y=1/6
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1:2x-y=5...1
x-2y=1...2 equation du1*2 minus equation 2 to get.
zhidao4x-2y-x+2y=9, that is, 3x=9, x=3, y=2x-5=1
2: Ibid. version, multiply Equation 1 by Weight 2 and subtract Equation 2 to get 14x+6y+5x-6y=19,19x=19,x=1
3y=5-7x=-2,y=-2/3
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(1) Transform x-2y=1 into a copy
get: x=1+2y and then substitute baix into 2x-y=5 to get y=1 and x=3
2) Multiply duzhi 7x+3y=5 by 2 on both sides to get 14x+6y=10-5x+6y=-9, subtract these two formulas to get 19x=19, i.e., x=1, and then take x=6y=10 to get y=-2 3
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(1) Solution:
baiy=2x-5 —du> substitution x-2(2x-5)=1 —> solution to zhi:x=3,y=1
2) Solution: 7x+3y=5 on both sides of the DAO with the same special time*2 —>14x+6y=10 —> subtracted from -5x+6y=-9 to get 19x=19, i.e., x=1, y=-2 3
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