The one dimensional equation is used to solve the problem of chickens and rabbits in the same cage

Solution: If there are x chickens, then rabbits have (20-x), which can be obtained from the question:

2x+4(20-x)=50

2x-4x=50-80

2x=-30

x=1520-x=5

A: There are 15 chickens and 5 rabbits.

If there are x chickens, there are rabbits (20-x).

Two legs per chicken and four legs per rabbit.

2x+4(20-x)=50

The solution is x=15

So there are 15 chickens and 5 rabbits.

Solution: If there are x rabbits, then there are 20-x chickens.

4x+2﹙20-x﹚＝50

4x+40-2x＝50

4x-2x＝50-40

2x＝10x＝10÷2

x 5 chickens; 20-5 15 pcs

Answer; There are 15 chickens and 5 rabbits.

If there are x chickens, then the chicken legs are 2x

20-x）*4+2x=50

x=15.

5 rabbits.

Solution: If there are x chickens, then the rabbits are (20-x).

Then the equation: 2x+4(20-x)=50

The solution is x=15

A: 15 chickens and 5 rabbits.

Solution: If there are x rabbits, then there are 20-x chickens.

4x+2（20-x）=50

4x+40-2x=50

2x=10x=5

20-5 15 pcs

The solution of the binary equation of chickens and rabbits in the same cage is as follows:

1. (Total number of feet, number of chicken feet, total number) The difference between the number of rabbit feet of each chicken = the number of rabbits.

2. The number of rabbits = (total number of legs and total number of heads 2) 2. <>

3. The number of chickens = (total number of heads 4 total number of legs) 2.

4. (Number of rabbit feet, total number of rabbits, total number of feet) The difference between the number of rabbit feet of each chicken = the number of chickens.

How to solve the equation of chickens and rabbits in the same cage:

If there are x chickens, then the rabbits have (total -x) because each rabbit has 4 legs and each chicken has 2 legs. So there are 2x chicken feet and 4 rabbit feet (total - x). So we can get the equation: 2x + 4 (total - x) = total full number.

Chickens and rabbits in the same cage is one of the famous mathematical problems in ancient China. About 1,500 years ago, this interesting question was recorded in the "Sun Tzu's Sutra". Here's how it is narrated in the book:

There are thousands of chickens and rabbits in the same cage, counting from above, there are 35 heads, and counting from below, there are 94 legs. Q: How many chickens and rabbits are in each cage? <>

The simplest algorithm for chickens and rabbits in the same cage: (total number of feet - total number of heads number of chicken's feet) (number of rabbit's feet - number of chicken's feet) = number of rabbits, i.e.

94-35 2) 2=12 (number of rabbits). Total number of heads (35) - number of rabbits (12) = number of chickens (23).

Unary Linear Equation Solution:

If there are x rabbits, there will be (35-x) chickens without a vertical stove. 4x+2 (35-x) =94, and x=12. Chickens: 35-12=23 (pcs).

If there are x chickens, then rabbits have (35-x). 2x+4(35-x)=94, and the solution is x=23. Rabbit: 35-23=12 (only).

There are x chickens and y rabbits. The system of equations is: x+y=35 2x+4y=94. x=23, y=12. A: There are 12 rabbits and 23 chickens.

There are many famous mathematical problems in ancient China, "chickens and rabbits in the same cage" is one of them, about 1500 years ago, "Sun Tzu's Sutra" recorded this interesting problem in the book is described as follows: "There are chickens and rabbits in the same cage today, there are thirty-five heads on it, and there are ninety-four feet under it. ”

How many chickens and rabbits are in the cage?

Solution: If there are x chickens, then rabbits have (35 x), which is derived from the title:

2x 4 (35 x) 94, solution: x 23, then 35 x 12

A: There are 23 chickens and 12 rabbits

Solution of the unary equation: If there are x rabbits, then there are (35-x) chickens. 4x+2 (35-x) =94, and x=12.

Chickens: 35-12=23 (pcs). If there are x chickens, then rabbits have (35-x).

2x+4(35-x)=94, and the solution is x=23. Rabbit: 35-23=12 (only).

Binary Equation Solution: Let there be x chickens and y rabbits. The system of equations is:

x+y=35 2x+4y=94。x=23, y=12. Answer;

There are 12 rabbits and 23 chickens.

There are x chickens and (20-x) rabbits.

2x+4（20-x）=50

2x+80-4x=50

2x=-30

x=1520-x=5

A: There are 15 chickens and 5 rabbits.

Description: (I am in the first year of junior high school, I have already learned the one-dimensional equation, I am in the sixth grade, it is very simple, and it is guaranteed to be 100% correct!) ）

If the number of chickens is x, then the chickens have 2x legs.

If the number of rabbits is y, then rabbits have 4x legs.

If the total number of chickens and rabbits given in the question is A, there are B legs.

Rule. x+y=a

2x+4x=b。

It is enough to solve the binary equation.

It is known that there are 30 chickens and rabbits, and a total of 84 feet.

Set up x chickens, rabbit y?

A system of binary linear equations can be listed.

x+y=30①;2x+4y=84②

①2:2y=24，y=12

x = 18 chickens and 12 rabbits.

Suppose the chicken finches and rabbits talk about a total of a and a total of b feet,'

If there are x chickens and y rabbits, then: x+y=a

2x+4y=b

There are x chickens.

Then there are 18-x rabbits.

The rabbit's feet are 24 fewer than the chicken's.

2x-4（18-x）=24

Solution x=16

There are 18-16=2 rabbits.

A: There are 16 chickens and 2 rabbits.

Equipped with x chickens.

2x-4（18-x）=24x=16

There are 16 chickens and 2 rabbits.

Set the chicken x only, the rabbit y only, and the column equation.

x+y = total number of birds.

2x+4y=total number of legs.

I didn't learn much about this at the time.