Who can C programming, help make up a A B C D E F J H

#include

void main()

int a,b,c,d,e,f,j,h;

cout<<"Please enter the data (a, b, c, d, e, f, j, h)."<>a>>b>>c>>d>>e>>f>>j>>h;

cout<<"a×b×c×d×e×f+j+h=""If you write like this, add it below.""using namespace std;"。If you write include, you won't add it. Personally, I don't think it's necessary to add "return 0" to the main function at the end, the effect is the same.

If you want to calculate a decimal number, change the "int" in it to "float", the former is an integer, and the latter is a floating-point type. And double is a double, with a larger range. Come on, the landlord, if you can't, slowly learn knowledge by accumulation, and no one will be born with it.

Just kidding, it won't be.

This can be calculated directly with the greedy method

Set up a station at 500 km to store 500 liters of oil... And then just go straight -

You don't think you should have explained this topic clearly.

There is no oil in the desert, so the title expresses that the car has to transport its own oil and store it. So you have to run back to carry oil often.

++ In front of the self-addition and then calculation.

In the last first calculation and then self-adding.

For example: int i=5, j=6;

int ret = 0;

ret = i++;// ret = 5; i=5;

ret = i; // ret =6; i=6;

ret = ++j; // ret = 7; j=7;

ret = j; //ret = 7; j=7;

For example, j++ is to use the value of j first, and then add one to it, and ++j is to add one and then apply its value...

Here's how to memorize it.

i;+ in the front, it is written as i first self-adding, that is, i = i + 1 first, and then i is assigned to other variables i++;

After that, it is written as i and then self-adding, that is, i is assigned to other variables first, and then i=i+1