Make a simple student grade system with C

1. First of all, define a number of reed structure student, which contains the information of the student.

2. Define two variables of type student, and save the grade information and temporary variables of all students.

3. Define a custom function to enter the student's grade information.

4. Realize the input of student information and calculate the total score.

5. In the main function, first define the ruler with 4 integer variables, save the total number of students, and control the variables of the loop.

6. Next, enter the total number of students and save it in the variable n.

7. Enter the information of all students and save it in the array arr.

8. Use 3 cycles to realize the sorting of students according to their student numbers. In the end, the total score of each student is output according to the student number.

First, define a student structure, including the student's student ID, name, course grade array (floating-point array of 4 elements), average grade, overall grade, and an identifier (indicating excellent, good, and average).

Second, define an array of structs with 50 elements, which is 50 students. and define excellent, good, and moderate variables to record the corresponding number of people;

Thirdly, set the score line of excellent, good, and medium, which can be entered or preset;

Finally, the average grade of each person is calculated and the excellent and good are determined. Medium, excellent, good, and medium variables +1 depending on the situation.

The members of the struct array are set according to the situation, and must have at least the student's name (or student number) and the course grade array.

Definition: Array a[50][4] 4 grades per student.

Definition: Array b[50] The average grade per student.

Definition: Array c[5] The number of people for each grade.

Write a for() to record the grade.

1. Find the average grade.

for(i=0,i<50,i++)

for(j=0,j<4,j++)

b[i]=b[i]+a[i][j]

b[i]=b[i]/4

2. Find the number of 5 kinds of results.

for(i=0,i<50,i++)

if(b[i]>=90) c[0]=c[0]+1;

else if (b[i] >=70 c[1]=c[1]+1;

That's it. I haven't written it for a long time, and there may be some grammatical errors, so you can change it.

It can be implemented with a linked list, which is easier to operate.

Let's use C++, object-oriented, one class to do it.