2 Biology questions in high school and 2 Biology questions in 2 high school

Updated on educate 2024-04-09
11 answers
  1. Anonymous users2024-02-07

    Vaccines are inactivated viruses, such as hepatitis B vaccines, which are inactivated hepatitis B viruses, and after being injected into the human body, the human body will produce antibodies, and when there is a truly active hepatitis B virus that invades the human body, the antibodies will work so that people will not get hepatitis B.

  2. Anonymous users2024-02-06

    d To see sign language, of course, the visual center should be involved, so there are 3 options; And because sign language is a language that needs to be processed by the brain to understand, there are 4 options;

  3. Anonymous users2024-02-05

    Question 1: Select C.

    Because 15 N first appeared in the nucleus and then transferred to the cytosol and ribosome, it means that the mRNA synthesized in the nucleus contains 15 N, and there can be no thymine on the RNA chain, so the labeled base cannot be thymine.

    The second question has 3 nucleic acid molecules and 4 strands, so it can be preliminarily determined to be a double-stranded DNA molecule and two single-stranded RNA molecules. From the fact that there are five bases (A, T, G, C, U), it can be determined that there are both DNA and RNA in the three nucleic acid molecules. The eight nucleotides also illustrate the problem of containing both DNA and RNA molecules, four types of deoxyribonucleic acid (AGCT) and four types of ribonucleic acid (AGCU).

    Please give me a point

  4. Anonymous users2024-02-04

    D, five bases to get DNA and RNA, 4 nucleosides to get 2 RNA, DNA is deoxynucleoside.

  5. Anonymous users2024-02-03

    1. The five carbon dioxide cannot be darkly reacted, and the five carbon molecules produced by the light reaction cannot be utilized 2. There seems to be a problem with the second question, and there is no problem with the shareholding question, which should be like this!

    aa aa aa hybridization generated.

    F1 1 2AA 1 2AAF1 was crossed with F1' to obtain progeny for.

    1 2aa aa get offspring.

    1 2*1 4aa purple flower 1 2*1 2aa purple flower 1 2*1 4aa white flower.

    The answer is 3 8

    If the answer is 1 6, it should be aa and aa

  6. Anonymous users2024-02-02

    RUBP cannot be synthesized with CO2 with hexacarbonate and consumes less.

    The six-carbon sugar can also be converted into RUBP under light, and the generation remains unchanged.

  7. Anonymous users2024-02-01

    1.Because of the sudden cessation of **CO2, the dark reaction of photosynthesis cannot be carried out, and the five-carbon molecules produced by the photoreaction cannot react at this time, and the solid increases.

    2.The title seems to be a bit problematic, and no matter how you calculate it, you can't calculate a 1 6

  8. Anonymous users2024-01-31

    1: The reduction of CO2 affects the dark reaction, making the CO2+C5 reaction slower, and the reduction of CO2 to C5 in the dark reaction remains unchanged, so C5 increases, (there is a C5 cycle in the book) 2: I don't know if the question is wrong.

  9. Anonymous users2024-01-30

    1) Volatile extractant, concentrated carotene extract.

    2) Prevent the volatilization of organic solvents during heating.

    3) Chromatography containers.

    4) Fully dissolve the water content.

    5) Without a glass cover, it will cause a large amount of solvent volatilization Carotene dissolves in the solvent without chromatography Prevents the carotene in the sample from diffusing at different heights of a and d.

  10. Anonymous users2024-01-29

    1.Answer: 21%.

    Analysis: First, it was deduced that the single strand of DNA (set to A strand) formed by RNA reverse transcription contained A=23% (matched with U in RNA) and T=19% (matched with A in RNA). Then, another complementary DNA single strand (set to B strand) was deduced from the A strand, which contained t=23% (paired with A complementary pairing in the A strand) and A=19% (matched with T complementary paired with T in the A strand). So for the whole DNA, the percentage of A is (23%+19%) 2=21%.

    2.Answer: 25%.

    Analysis: The template strand of the transcribed mRNA gene contains g=27%, c=23%, then the complementary strand of the other template strand contains c=27%, g=23%, so the content of g in the template gene is (27%+23%) 2=25%.

  11. Anonymous users2024-01-28

    1、a=19%--t=19%

    c=26%--g=26%

    g=32%--c=32%

    u=23%--a=23%

    After copying, it is like this, and then (19%+23%) 2=21%2, the same as that.

    a=24%--t=24%

    u=26%--a=26%

    c=27%--g=27%

    g=23%--c=23%

    This is the content on the template, and then (23%+27%) 2=25% is recommended to study hard.

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