Math Problem !!!! 30 minutes, urgent! 30 points for math problems!!

1) If you set a small red x sheet, then Xiao Ming has a (171-x) sheet.

Column equation: x=76 Xiao Hong, Xiao Ming 95 sheets.

2) Set Xiao Ming x sheets, then Xiao Hong (171-x) sheets.

Column equation: get x=95 Xiao Ming 95 sheets, Xiao Hong 76 sheets.

3) Let the quarter of Xiao Hong and the fifth of Xiao Ming be the equation of x: 4x+5x=171

Solve the equation: x=19

So, Xiao Hong has 4x=76 and Xiao Ming has 5x=95.

That's three types, right?

1. Set Xiao Hong x sheets, then Xiao Ming 171-x sheets:

1/4x＝（171-x）×1/5

x＝76,1x/5＝95.

2. Set up Xiao Hong x Zhang, Xiao Ming Y Zhang:

x+y＝171,1x/4＝1y/5

x＝76,1x/5＝95.

3. Set small red x sheets, then Xiao Ming 1x 4 1 5 5x 4 sheets x+5x 4 171

x＝76,1x/5＝95.

1.Set Xiaohong has x sheets, and Xiao Ming has Y sheets.

1/4x=1/5y

x+y=171

Solution: x=76, y=95

2.Let a quarter of the little red be x

4x+5x=171 gives x=19

Xiao Hong has 4x19=76, and Xiao Ming has 5x19=953There are x sheets of small red.

x+5/4 x=171x=76

High The circumference of the square.

The circumference of the square is 4

So the height of the rectangle is 4 times the length of the sides of the square.

Because the bottom surface is a square, let its bottom side length be 1, and the bottom edge of the side view is the sum of the edges of the four bottom surfaces, that is, 4, so the side length of the square formed by the figure is 4, so the height is 4 times the length of the square side.

4 times. Its bottom surface is also square, and if the side length is a, the circumference is 4a

The side view is a square, and if the side length is b, then b = 4a

1 times, because the cube can also be a kind of cuboid, but it is a special cuboid, so in this question this cuboid is the special, the length and width of the cube are equal, then the height of the rectangle is equal to the length of the side of the square.

So the answer is 1 times.

4 times the height = bottom edge length and = 4 times the edge length to make the figure square.

It's supposed to be the height of the cuboid, it's so simple, 100 points you bluff.

It's late....Can you make another difficult one?

(again 6 11 + (again 6 11) + again 5 11) = (again 6 11 + (again 6 11) + again 5 11) = (again 6 11) + again 5 11).

6 11) + 5 11).

6 11 + 7 5 11).

(again 6 11 + (again 6 11) + again 5 11) = [again 6 11) + again 5 11).

6 11) + 6 11).

I've been super long. Calculate this number,

1.Figure A is a rectangle, known width is, figure B is a parallelogram, the lower base is known to be, figure C is a right triangle, the lower base is, figure D is trapezoidal, the lower base is, the upper bottom is.

The largest area is (c), the smallest is (b), and the equal area is (a) and (d).

2.Find the area of the trapezoidal shaded part in the figure below. (in cm) height = 3 4 5 = cm.

Area=1 2 square centimeters.

1. The largest area is (c), the smallest area is (b), and the equal area is (a) and (d).

2. The shaded part of the face is squared in centimeters.

Area of the non-shaded part = 3x4x (1 2) = 6 trapezoidal area = (5 + 12) x (1 2x5) x (1 2) = area of the shaded part = trapezoidal area - area of the non-shaded part =

The first question is that you take a ruler and measure it, and you can measure it in the regular exam.

Question 2 (5+12)*(12 5) 2=102 5

The largest area is c and the smallest is b and the equal is AD shadow interview.

Suppose there were 12x pieces.

12x*(5/12)+4=(12x+4)/25x+4=6x+2

x=2, so now there are 12*2+4=28 pieces.

Harvest as much.

Assuming the unanimous vote is 1, then the first case is 1+1+;

The second case is (1+1+1)*

The same, both are times the full price.

The distance between the two places is 390 meters, (s-75) (65+40)=s 2 65 solvable.