A few simple factorizations A simple factorization

=(x+2-1)(（x+2)(x+2+1)-(7-1)*7*(7+1)

(x+2-1)(x+2+1)(x+2)-(7-1)*(7+1)*7 (in this step, x+2,7 is treated as a number, using the squared difference formula).

(x+2)^2-1]*(x+2)-(7^2-1)*7=(x+2)^3-(x+2)-7^3+7

x+2-7)[(x+2) 2+7(x+2)+7 2]-(x-5) (equivalent to a3-b 3).

x-5)[(x+2)²+7(x+2)+7²-1]= (x-5)(x^2+11x+66)

1. 4a²-b²-2a+b

2a-b）(2a+b)-(2a-b)

2a-b)(2a+b-1)

2. a²（b+1）-b²（a+1)

a²b+ a²-ab²-b²

a²b-ab²+a²-b²

ab(a-b)+(a-b)(a+b)

a-b)(ab+a+b)

4ab-4 a²-b²

(2a-b)²

4.（a-b）（a²-ab+b²）-ab（a-b）=(a-b)（a²-ab+b²-ab)

a-b))^3

5. a²（a-b）²（m-n）+b²（b-a）²（n-m）=(a²-ab)²(m-n)-(b²-ab)²(m-n)=(m-n)(a²-ab+b²-ab)(a²-ab-b²+ab)=(m-n)(a²-2ab+b²)(a²-b²)=(m-n)(a+b)(a-b)^3

Find: When b +2ab = c +2ac, b -c = 2ac-2ab(b-c)(b+c) = 2a(c-b).

If b and c are not equal, then b+c=-2a, abc cannot be negative, which contradicts what is known. So b=c, abc is an isosceles triangle.

x -71x+300: The question is wrong, if it is x -71x-300, then = (x+4)(x-75).

6x²-25x-9=(3x+1)(2x-9)6x²-25x+24=(3x-8)(2x-3)8x²+73x+72=(x+8)(8x+9)8x²-189x-72=(x-24)(8x+3)