The equation about x 3 2x x 3 2 m x 3 x 1 has no solution, find the value of m.

Well, there is no square in the process, and the value of m is not 3

Solution: 3-2x) (x-3)+(2+mx) (3-x)=-13-2x) (x-3)-(2+mx) (x-3)=-1 multiplied by (x-3) on both sides at the same time

3-2x)-(2+mx)=-(x-3)

3-2x-2-mx=-x+3

x-mx=2

1+m)x=2

x=-2/(m+1)

Classification discussion, to make the original equation unsolved, 1) x = 3 (x = 3 is the root of the equation), obtain.

1+m)*3=2

m=-5/3.

2) 1+m=0, then the value of x is meaningless, m=-1, in summary, when m=-1 and -5 3, the original equation has no solution.

What is the title, is it okay to add some parentheses to 3-2x x-3+2+mx 3-x=-1? I can ask and hope it can help you.

Solution: 3-2x) (x-3)+(2+mx) (3-x)=-13-2x) (x-3)-(2+mx) (x-3)=-13-2x)-(2+mx)=-(x-3).

3-2x-2-mx=-x+3

x-mx=2

1+m)x=2···

To make the original equation unsolved, let x=3 (x=3 is the root of the equation), get.

1+m)*3=2

m=-5/3.

In addition, for the equation, if 1+m=0, then x=0, but at this time, the two sides of the original equation are unequal, so x≠0, so to make the original equation unsolved, just make 1+m=0, that is, m=-1, in summary, when m=-1 and -5 3, the original equation has no solution.

3-2x/x-3+2+mx/3-x=-1

Multiply the two sides of the equation by x-3.

3-2x-2-mx=-(x-3)

1-m)x=2

When -1-m=0 or x=3 (root resistance), none of the original equations are solved.

When -1-m=0, then m=-1

When x=3 (Zengchang lacks brother root), (-1-m)*3=2, then m=-5 3 So when m=-1 or m=-5 3, the equation 3-2x x-3+2+mx 3-x=-1 has no solution.

Knowing that x=-2 is the solution of the equation (x+m)-(mx-3)=3x about x, then substituting x=-2 into the equation (x+m)-(mx-3)=3x obtains:

2+m）-(2m-3)=3*(-2)-2+m+2m+3=-6

m=-7/3

Solution: 3-2x) (x-3)+(2+mx) (3-x)=-13-2x) (x-3)-(2+mx) (x-3)=-13-2x)-(2+mx)=-(x-3).

3-2x-2-mx=-x+3

x-mx=2

1+m)x=2···

To make the original equation unsolvable, let x=3 do, and get.

1+m)*3=2

m=-5/3.

In addition, for the formula, if 1+m=0, then x=0, but at this time, the two sides of the original equation are unequal, so x≠0, so to make the original square range unsolved, just make 1+m=0 that is, m=-1, to sum up, when m=-1 and -5 3, the original equation has no solution.

3-2x/x-3+2-mx/3-x=﹣1

3-2x+mx-2=3-x;

m-1)x=2;

x=2/(m-1);

So 2 (m-1)=3;

m-1=2/3;

m=5/3;

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Multiply by x-3.

3-2x)-(2-mx)=3-x

3-2x-2+mx=3-x

3-2x-2+mx=3-x

mx-2x+x=2

m-1)x=2

If there is no solution, then. m-1=0 or solution as root-increasing x=3

m=1x=3.

3(m-1)=2

m-1=2/3

m=5 3, so m=1 or m=5 3

The equation has no solution is to tell you that the root formula of the above equation is less than 0. The equation for finding the root is less than 0, and this inequality is the value of m.

The basic steps of the fractional equation solution method can be simplified to the following criteria.

x-mx-2=0

When x=3, the equation is unsolved:

3-3m-2=0

m=-5/3