Ask for answers! Mathematical calculations, please help calculate! Mathematics

Solution: (1) Let the highway distance between Zhoushan and Jiaxing be S kilometers, and the solution is S=360 from the title, S 4-S, so the highway distance between Zhoushan and Jiaxing is: 360 kilometers;

2) The calculation method of the highway toll Y (yuan) of the car is: Y = ax + b + 5, according to the toll fee of ** and Mr. Lin, y = , x = 360-48-36 = 276, b = 100 + 80 = 180, they are substituted into y = ax + b + 5, and the solution is a =, so the highway mileage of the car is: yuan kilometers

Hello, the answer you want is: A1

o---b moment tab 2 a0 2 + bo 2

Derivative of t. 2ab dab dt 2ao dao dt 2bo dbo dt12:30, ao bo= 16* =8 ab= 10dao dt=-24 dbo dt=16 substitution to get dab dt

1) Over e as EF is parallel to AB, because AB is parallel to EF, so the angle ABE=angle BEF=N 2 degrees.

Because EF is parallel to AB AB is parallel to CD, so EF is parallel to CD, so the angle fed = angle EDC = 35 degrees.

So the angular bed=(35+n2) degrees.

2) Over E as Fg is parallel to AB, because AB is parallel to EF, so the angle ABE=BEF=N 2 degrees.

So the angle beg=180-n2 because ef is parallel to ab ab so ef is parallel to cd so the angle ged=angle edc = 35 degrees, so the angle bed=215-n 2 degrees.

<> clear enough? Step by step.

Tell me about your teacher** I'll help you ask (

x²＋2x＝o

x﹙x＋2﹚＝0

x＝o x＝﹣2

2. x²－8x＋15＝0

x－3﹚﹙x－5﹚＝0

x＝3 x＝5

3. x²-2x－99＝0

x²－2x＝99

x²－2x＋1＝99﹢1

x－1﹚²＝100

x＝11 x＝﹣9

4. 5x²＋2x﹣1＝0

5（x²+2x/5+1/25）=6/5

x+1/5）²=6/25

So x+1 5= root number 6 5

x=(-1 root number 6) 5

5. 2﹙x－4﹚²＋16＝x²

x²－16x﹢48＝o

x²－16x﹢8²＝﹣48﹢64

x﹣8﹚²＝16

x＝12 x＝4

Hope it helps, (*hee-hee......