Math problems, please master answer, math problem solving, master please enter

Updated on educate 2024-04-06
20 answers
  1. Anonymous users2024-02-07

    1 9000000 = 117000000cm = 1170km m = 3000 cm, 20 m = 2000 cm.

    Above: length = 3000 1 1000 = 3 cm, width = 2000 1 1000 = 2 cm.

    3. Actual distance = 8 1: 200000000 = 160000000 cm = 1600 km.

    1600 600 = 2 and 2 3 hours.

    A: It takes 2 and 2 to 3 hours to arrive.

  2. Anonymous users2024-02-06

    1: 9000000 = 13 cm: x, x = 117000000cm = 1170km

    Length = 30 m * 1/1000 = 3cm Width = 20 m * 1/1000 = 2cm

    The actual distance between the airports of A and B is 8 cm (1:20000000) = 1600km, 1600 600 = 8 3 hours.

  3. Anonymous users2024-02-05

    13 * 9000000 = 117000000 cm = 1170 km.

    30 1000 = m = 3 cm.

    20 1000 = m = 2 cm.

    8 * 20000000 = 160000000 cm = 1600 km.

    1600 600 = 2 and 2 3, i.e. 2 hours and 40 minutes to arrive.

  4. Anonymous users2024-02-04

    On a map with a scale of 1:9000000, the distance between A and B is 13 centimeters, how many kilometers is the actual distance between A and B?

    1:9000000=13:x

    x = 117000000 cm = 1170 km.

    The actual distance between A and B is 1,170 km.

    The basketball court is 30 meters long and 20 meters wide, and how many centimeters should be drawn on a drawing with a scale of 1/1000 scale?

    Length = 3000 1000 = 3 cm.

    Width = 2000 1000 = 2 cm.

    On the map of sub 1:20000000, the distance between the airports of A and B is 8 cm A famous technology flies from Airport A to Airport B at a speed of 600 kilometers per hour, and it takes several hours to arrive?

    It takes about an hour to arrive.

  5. Anonymous users2024-02-03

    1) 13cm*9000000=117000000cm=1170km

    2) The length is 30m*1 1000=3cm, and the width is 20m*1 1000=2cm

    3) The actual distance is 8*20000000=16000000cm=1600km, and the time is 1600 600=8 3 hours is approximately equal to hours.

  6. Anonymous users2024-02-02

    Let pq=qr=rs=unit 1

    Then s1 = area of the great circle - area of the middle circle = *3 2 - 2 2 = 5

    s2 = area of the middle circle - area of the minor circle = *2 2 - 1 2 = 3

    Hence s2 s1 = 3 5 = 3 5

  7. Anonymous users2024-02-01

    How is S2 a ring and an area?

  8. Anonymous users2024-01-31

    Let's say that the radius of the great circle is r, the minimum radius of the circle is r, and the relation r=3r is satisfied, then it is fine.

  9. Anonymous users2024-01-30

    Let pq=qr=rs=a, then ps=3a, pr=2a, so s1=(3a) 2 -2a) 2 =5a 2 in the same way s2=(2a) 2 -a 2=3a 2 so s2 s1=3 5 i.e. three-fifths.

    Got it?

  10. Anonymous users2024-01-29

    A 43, B 24

    Let the age difference between A and B be x

    Then 5+x is the age of B, and 62-x is the age of A (62-x) -5+x) = x

    57 - 2x = x

    x = 19

    62-x=43

    x+5=24

  11. Anonymous users2024-01-28

    Let A's age be x and B's age be y

    x-y=y-5

    y-x=x-62

    Solution: x=43, y=24

  12. Anonymous users2024-01-27

    Let A be x years old, B y years old, and the equation is:

    2×y-x=5

    2*x-y=62

    In the end, A is 43 years old and B is 24 years old.

  13. Anonymous users2024-01-26

    The principle is that the sum of the sections is as close as possible, so that it is the most economical.

    1), 10 roots, 10 left, 5 pieces.

    3 pieces, 3 roots, 1 left, 2 pieces, 1 root.

    There are 14 sticks in common.

    2), 5 are needed, 20, 15, 5 are left.

    5 are needed, 15 are left, 10 are left.

    3 pieces, 5 roots, and the remaining 5 pieces, 2 roots.

    There are 17 in total.

  14. Anonymous users2024-01-25

    1.roots of wood, cut 10 each)

    Roots of wood, of 9 roots, of 3 roots).

    Roots of wood, of 1 root, of 2 roots).

    Total required: 10 + 3 + 1 = 14 roots.

    2.1+ sticks of wood, 1 m and 5 of each).

    Root wood4 of each cut 5 roots)

    roots of wood, of 15 roots, of 5 roots).

    Roots of wood, of 5 roots)

    Total required: 5+5+5+2=17.

  15. Anonymous users2024-01-24

    .4+, 10 needed, 10 left, 5.

    3 pieces, 3 roots, 1 left, 2 pieces, 1 root.

    There are 14 sticks in common.

    8+1=,,5 left, 20 left, 15, 5, 5, 15 left, 10 left.

    3 pieces, 5 roots, and the remaining 5 pieces, 2 roots.

    There are 17 in total.

  16. Anonymous users2024-01-23

    What grade are you in?

    If this is a college operations research problem, it's just a practice problem.

    If you're a high school or just a junior high school student, it's complicated. It's a lot of computation.

  17. Anonymous users2024-01-22

    No matter how you cut this, you will have leftovers of rice, because your selection of materials is even. Your timber is long meters You cut 3 meters of 1 rice leftovers.

  18. Anonymous users2024-01-21

    This is this year's junior high school math contest question, but you copied the wrong question.

    For any real number x,y,z, define the operation "*is: x*y=(3x 3y+3x 2y 2+xy 3+45) [(x+1) 3+(y+1) 3-60], and x*y*z=(x*y)*z, then 2013*2012*......3*2=?

    Solution: When y=3, x*3=(9x 3+27x 2+27x+45) (x 3+3x 2+3x+5)=9, so the original formula=9*2=(4374+1083+72+45) (1000+27-60)=5574 967.

    Is that okay?

  19. Anonymous users2024-01-20

    1,3 packets of chocolate:

    That is, each pack of chocolate chips is yuan.

    That is, from day 4 onwards, read at least 29 pages a day.

    Kilogram = 2750 grams.

    That is, Director Zhang needs kilograms of this oil, which should be 990 yuan.

  20. Anonymous users2024-01-19

    1;The price of each pack of Shanghaojia is yuan, and each package of chocolate beans is yuan.

    2;(150-5) (8-3) = 29 pages.

    3;500+ grams.

    Kilogram = 2750 grams.

    198*5=990 yuan.

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