Junior 1 math problems Please!

** The above is the problem-solving process.

1. Solution: original formula = -3 12 + 10 12 + 18 12-24 12 = (-3 + 10 + 18-24) 12 = 1 12

2. Solution: original formula = -3 2 1 4 = -3 8

3. Solution: original formula = -26 41 + 35 17 = -1066 + 595 = -4714, solution: original formula = 1 5 + 16 4 = 5 + 4 = 95, solution: original formula = -(-2) + 9 (-2) = -2-18 = -16

1.Original = -3 12+10 12+18 12-24 12=1 122Original = -3 8

3.Original = - (35x17-26x41) = -4714Original = 5 + 4 = 9

5.Original=2+9x(-2)=-16

The so-called process is to write down what you think or calculate on the straw paper, just write two steps, and finally the answer is good.

1.Original = -3 12+10 12+18 12-24 12=1 122Original = -3 8

3.Original = -1066 + 595 = -471

4.Original = 5 + 4 = 9

5.Original = 2-18 = -16

The implementation of the small time to recite the poetry book on the market, the small time to recite the poetry book on the market, in fact.

It's all oral arithmetic, you want the process? How embarrassing!

1 (1 stuffy 10 + 1 15) = 6

6 Ant State Judgment 15=

450*A.

450* already.

As follows: if x days are made, then x 10 + x 15 = 1, and x = 6 is solved, so A and B each do it.

6 Closed argument 15=

Money for. 450*A.

450* already.

This problem can be solved without the equation slow lead.

450 (450 10 + 450 15) = 6 (days) 450 10 6 = 270 (yuan).

450 15 6 = 180 (yuan) disturbing width.

Answer: A gets 270 yuan for Jiling, and B gets 180 yuan.

1.These are two consecutive three rational numbers, and the sum is 2*23=46, so a=8, -12+h+a=23, h=27, and t can be obtained as 83The law is 8, -12, 27, 8, -12, 27, 8, -12, 27 ,...8,-12,27

2010 is a multiple of three, so it should be 27 (27 is a multiple of 27).

Solution: Since the sum of the rational numbers in any three consecutive squares is 23, there is:

t+(-12)+h=23...1)-12+h+a=23...2)a+n+k=23...

3)n+k+8=23...4) From (1) and (2) can be deduced t=a

Posts (3) and (4) can be pushed out a=23

Substitution by equal amount, so t=a=23

I shouldn't need to continue to analyze it in the future, this little classmate should be able to figure it out!

t=。a=。k=27。

Children, count the rest. -

Let the speed on the ordinary highway be x, then the speed on the highway is (x+45), and the equation of the time off series is obtained:

600 x=2[480 (x+45)] x=75, so the time required to get from A to B by highway is 480 (75+45)=4h, good luck learning progress!

The average speed set at x km h on a normal highway is 45 x km h on a motorway

600/x /2 = 480/(45＋x)x= 75

The time required for the bus to travel from A to B by highway is 480 (75+45)=4 hours.

4 hours, set the speed of the ordinary highway is x, establish a system of equations equal to the speed, you can calculate the speed of the ordinary road, you can know the speed of the highway, you can know the time.

Substituting x=2 into gives 3=(2+a)-2, and gets a=3

The original equation becomes (2x-1) 3=(x+3) 3-2

Get x=-2

Substituting x=2 into gives 3=(2+a)-2, and gets a=3

The original equation becomes (2x-1) 3=(x+3) 3-2

x=-2 guaranteed! Do it!

Answer: 2x-1 3=x+a 3-2

Because the right -2 term is not multiplied by 3 when the denominator is removed, the result of removing the denominator is 6x-1=3x+a-2, and the solution is x=(a-1) 3=2, so a=7 can be found

2x-1/3=x+a/3-2

The correct solution is x=(a-5) 3

If a=7 is available, then x=(7-5) 3=2 3

n=3 then mn=9 select a

So it's 6 times a monomial, and the coefficient is one-half (1, 2).