-
Anonymous users2024-02-07When x<=-3, |x+3|+|x-4|+|x+1|=-3x, with a minimum value of 9
When -3<=x<=-1, |x+3|+|x-4|+|x+1|=-x+6 with a minimum value of 7
When -1<=x<=4, |x+3|+|x-4|+|x+1|=x+8, with a minimum value of 7
When x>=4, |x+3|+|x-4|+|x+1|=3x, there is a minimum value of 12 In summary, the minimum value is 7, and x = -1
-
Anonymous users2024-02-06x -3.
x+3|+|x-4|+|x+1|
x-3-x+4+-x-1
3x 93 x -1.
x+3|+|x-4|+|x+1|
x+3-x+4-x-1
x+67≤-x+6≤9
1 x 4 hours.
x+3|+|x-4|+|x+1|
x+3-x+4+x+1
x+87≤x+8≤12
x 4. x+3|+|x-4|+|x+1|x+3+x-4+x+1
3x+8≥20
So |x+3|+|x-4|+|x+1|The minimum value of is 7, where x = -1
-
Anonymous users2024-02-05Do it with geometric methodsx+3|+|x-4|+|x+1|It is the sum of the distances from one point to -3, 4, and -1 on the coordinate axis, and the coordinate axis is drawn, and -1 is in the middle of -3 and 4, because |x+1|>=0, so the x sought should be in the interval [-3,4], in this case|x+3|+|x-4|=7, when x=-1, |x+1|=0，|x+3|+|x-4|+|x+1|There is a minimum value of 7
-
Anonymous users2024-02-04Summary. An absolute value refers to the absolute value of a real number, i.e., its plus or minus signs are not taken into account, only its magnitude is considered. The zero point is a number with an absolute value of zero, i.e., 0.
An absolute value refers to the absolute value of a real number, i.e., its plus or minus signs are not taken into account, only its magnitude is considered. The zero point is a number with an absolute value of zero, i.e., 0.
How is the zero point of the absolute value determined.
There are many ways to determine the zero point of the absolute value, that is, 0, the simplest difference is to compare the number with the size of 0, if it is 0 or less than 0, the absolute value of the number is 0. In addition, the zero point of the absolute value function can also be determined by the derivative method, that is, when the derivative of the function is 0, the value of the function is the zero point.
-
Anonymous users2024-02-03If the answer is 7km, then I think the problem should be that you only need to send it to A, B, and C stores, and if you need to go back to O, you have to go 10km, first from O to the north, and then to B, and then to the number of C, and finally to A,
-
Anonymous users2024-02-02When the absolute value symbol is opened, it is:
x+(x-1)+(x-2)+(3-x)+(4-x)+(5-x)=9
-
Anonymous users2024-02-019 The process is as follows: because x=6005 2002 so x, x-1, x-2 are greater than zero.
So |x|+|x-1|+|x-2|+|x-3|+|x-4|+|x-5|=3x-3+12-3x=9
-
Anonymous users2024-01-31On the number line, the absolute value of a number represents the distance (from the origin), and the farther away from the origin, the greater the absolute value. Since the distance is always positive and 0, the absolute value of a rational number cannot be (negative), that is, a takes any rational number, and there is 丨a丨( )0
Rational numbers whose absolute value is equal to the same integer have (0,1) and they (absolute value equal to themselves).
-
Anonymous users2024-01-30I don't know if that's right!
1 The absolute value of a number represents the distance (from the number to the origin)2 The farther away from the origin, the absolute value (the smaller).
3 then the absolute value of a rational number cannot be (is a negative number), and 4 has 丨a丨 (greater than or equal to) 0
The last empty is incomprehensible.
-
Anonymous users2024-01-29This counts to the origin.
The greater the negative number. Greater than or equal to.
Both positive and absolute values of 0 are equal to themselves.
-
Anonymous users2024-01-281.A number of distances to the origin2The bigger the 3Negative number 4Greater than or equal to.
-
Anonymous users2024-01-27Distance from the origin.
The greater the negative number. Greater than or equal to.
I don't know about the back 2.
-
Anonymous users2024-01-26x is greater than or equal to 2:10-x
2 less than or equal to x less than or equal to 2: 5x-2
x is less than or equal to 2:2-5x
-
Anonymous users2024-01-25The answer is c, because the absolute value x+1 is positive on the definition domain, and the absolute value can be directly removed, while x-1 is - on the definition domain, to become x-1 in the absolute value.
-
Anonymous users2024-01-24|3x-1|+2=0， |3x-1|=-2 0, obviously not true, so there is no solution.
-
Anonymous users2024-01-23This needs to be discussed in a categorical manner.
x 0, |-x|=x
When x 0, |-x|=-x
Refer to the upstairs, but upstairs doesn't know then without adding a statement? >>>More
Summary. Kiss. Hello, the question of shoes 1, see whether the upper and bottom of the shoe are completely fitted, whether there is glue, whether there are holes. >>>More
Hello: We know that the VAT payable in the current period = the output of the current period - the input of the current period, we all agree with this, so we can see from the question that the sales of the current period is the output tax of 400 sets of equipment, and the input tax of the current period is the input tax of 500 units, so why should the current output subtract the current input? The reason is that the input tax is to be deducted, so after the input tax is subtracted from the output tax, isn't it the purpose of the deduction? >>>More
Multiple independent events are probable.
Answer: Each card has a probability of 1 5 on each slot and does not affect each other. >>>More
Categorize 1 to 50 and divide them into 7 divided by 7 and divisible by 7, with 8 remaining 1 and 1 remaining and 7 others. In the same way, the elements of the remaining 2 and the remaining 5 cannot exist at the same time, the remaining 3 and the remaining 4 cannot exist at the same time, and the divisible can only exist in one element at most, so at most there are 8 remaining 1, the remaining 2 or 5 choose one category, the remaining 3 or 4 choose one category, and the divisible one can be selected, a total of 23.