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Anonymous users2024-02-07x+1 3, so divide the two sides by x+1, then there is 3/1 (x+1);
Because. 2 x+1, divide both sides by x+1, then there is 2 1 of (x+1), multiply 3 2 on both sides, and there is.
x+1) 3/2
By the transitivity of inequalities, there is.
3/3 of 1 (x+1) 3/2
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Anonymous users2024-02-06If you can't get that result, you must have miswritten the two "of the result", is it possible that 1 will be less than 2 3?
I think you should be trying to fight.
How to get 1 (x+1) 3 2 3" from 2 x+1 3".
2 x+1 3 can be split into x+1 2 (1) and x+1 3 (2);
From (2) (x+1) 3 1
From (1) we get (x+1) 3 2 3
Together, it's 1 (x+1) 3 2 3
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Anonymous users2024-02-052≤x+1≤3
2 x+1 and x+1 3
From 2 x+1, the transformation yields: 1 (x+1) 1 2, then 3 (x+1) 3 2
From x+1 3, the transformation yields: 1 3 1 (x+1), then 1 3 (x+1)1 3 (x+1) 3 2
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Anonymous users2024-02-04Mistakenly, it should be 2 3 (x+1) 3 1.
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Anonymous users2024-02-03x=2 ( 3-1)= Li Nianchen 3+1,1 x=( high collapse 3-1) 2,x+1 x= 3+1-( 3-1) 2
If you have any questions, please ask; If you are satisfied, thank you!
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Anonymous users2024-02-02x+1/x=3
Multiply both sides by xx +1 = 3x
square x 4 + 2 x + 1 = 9x
Subtract x from both sides
x^4+x²+1=8x²
So x x 4 + x +1 = 1 8
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Anonymous users2024-02-01Is x -x fraction x 2 + 1 x 2.
then, x + x one.
x-1/x)^2+2
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Anonymous users2024-01-31The square of (x+1/x) is x-square + (1/x) square + 2=11
The square of x-x-x-x
So the answer is plus or minus the root number 7
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Anonymous users2024-01-30(x-x) 2=(x+x/x) 2-4=5
x-x parts = root number 5
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