Olympiad problems, list the columns, Olympiad problems to column .

The ** of the book is yuan.

You can use the equation to set the book as x, then Xiao Gang's money is Xiao Ming's money, and the sum of the two is x

Xiao Gang's money should be 0 and there is x

Therefore, x=in fact, Xiao Gang has no money, Xiao Ming has yuan).

This book requires the amount of money to be dollars.

Because Xiao Ming lacks 1 point, and the money of the two people together to buy a book is still not enough, so Xiao Gang has no penny, so the amount of money that Xiao Gang lacks is the money of the book.

The question of the real two.。。。 The Olympiad kills people.

Set this book to be x yuan, then Xiao Gang has a yuan, and Xiao Ming has a yuan, together the two have a total of yuan, according to the title, so x>=, so x=, that is, this book to 2 yuan 8 corners.

Yuan Because Xiao Ming is short of 1 point, and the combined money of the two people is still not enough to buy a book (that is, the money of Xiao Ming and Xiao Gang is still not enough to buy a book);

That is to say, Xiaogang's money is less than 1 point, that is, Xiaogang has no money;

And Xiaogang lacks 2 yuan and 8 jiao, which means that the 2 yuan and 8 jiao is the price of the number.

3 is added in front of it, which is equal to the original number plus 300

3 is added to the end, equal to 10 times the original number plus 3

The difference between the two times is equal to 10-1 = 9 times the original number minus 300-3 = 297 original number: (351 + 297) 9 = 72

1. There are 40 students in a class, of which 15 participate in the mathematics group, 18 participate in the model aircraft group, and 10 people participate in both groups. So how many people don't participate in both groups?

2. After the results of a class of 45 students took the final exam, 10 students got full marks in mathematics, 3 students got full marks in mathematics and Chinese, and 29 students did not get full marks in these two subjects. So how many people got a perfect score in Chinese?

A student stood in a line facing the teacher. The teacher first asks everyone to press 1, 2, 3 ,...... from left to right49,50 in turn; Then ask the student who reported a multiple of 4 to turn back, and then let the student who reported a multiple of 6 turn backward. Q:

How many students are there for teachers now?

4. At the amusement fair, 100 students drew lottery tickets with labels from 1 to 100. The rules for awarding prizes according to the ticket tag number are as follows: (1) If the tag number is a multiple of 2, 2 pencils will be awarded; (2) If the label number is a multiple of 3, 3 pencils will be awarded; (3) The label number is both a multiple of 2 and a multiple of 3 to claim the award repeatedly; (4) 1 pencil will be awarded for other label numbers.

So how many prize pencils are there for this event?

5. There is a rope with a length of 180 cm, starting from one end of the pin to make a mark every 3 cm, and every 4 cm to make a mark, and then cut the marked place. Q: How many pieces of rope have been cut?

Answer to 5th grade question 3.

1. Because 10 people and 2 groups participated, 5 people only participated in mathematics, 8 people only participated in model aircraft, plus those 10 people were 23 people, 40-23 = 17, 17 people who did not participate in 2 groups.

2. In the same way, there are 10 people with a full score in mathematics and 3 people with a full score in 2 subjects, so there are only 7 people with a full score in mathematics, 45-7-29 = 9, this is the person with a full score in Chinese (if it is only a full score in Chinese, you need to subtract 3).

3,50 4 round 12,50 6 round 8, but note that the multiple of 4 may be a multiple of 6, so you also need to calculate the common multiple of 4 and 6, there is 50 12 (the least common multiple of 4 and 6) = 4 (rounded), so, it should be 50-12-8 + 4 = 34

4,100 2=50,100 3=33 (rounded), or calculate the common multiple of 2 and 3 100 6=16 (rounded), and then find the number of numbers that are not divisible by 2 and not divisible by 3 100-50-33+16=28, so prepare a pencil for 50x2+33x3+28=227

5,180 3=60,180 4=45, but maybe 2 dashes are drawn together, that is, to calculate their common multiples, 180 3 4=15, so it should be 60+45-15=90

That is, 6 trees in a group.

That is, there are 16 groups and 4 more trees.

The fourth tree in the group with many is a large green peach.

So the 100th tree is a large green peach.

There are 16 groups and 4 more trees.

Therefore: there are 16 * 1 + 1 = 17 peaches.

There are peaches: 16 * 2 + 2 = 34 trees.

There are 16 * 3 + 1 = 49 green peaches.

I hope mine is helpful to you, o(o!

6 trees as a group, the order is: peach, peach, peach, peach, peach, peach, peach.

100 6 = 16 and 4

The 100th tree is the fourth tree in a group, which is a large green peach.

Number of peaches = 16x1 + 1 = 17

Number of peaches = 16x2 + 2 = 34

Number of large green peaches = 16x3 + 1 = 49

1 peach, 2 peaches, 3 large green peaches, a total of 6.

100 6 = 16 surplus 4, the front are arranged according to 1 peach, 2 peaches, and 3 large green peaches.

The remaining 4 are 1 peach, 2 peaches, and 1 large green peach.

So the 100th tree is a large green peach.

A total of 1 * 16 + 1 = 17 peaches.

A total of 2 * 16 + 2 = 34 peaches.

A total of 3 * 16 + 1 = 49 large green peaches.