Line test Xiao Zhao Xiao Qian Xiao Sun played badminton together, and two people played each game

b First of all, we need to know how many games have been played in total, because Xiao Zhao has rested for two games, which means that there are two games played by Xiao Qian and Xiao Sun, which means that Xiao Qian and Xiao Zhao played 6 games (Xiao Qian played a total of 8 games - 2 games with Xiao Sun = 6 games), and in the same way, Xiao Sun and Xiao Zhao played 3 games (5-2), which means that a total of 11 games were played (2 + 6 + 3 = 11). We have all figured out what we know is available. I still can't tell who played with whom in the ninth game, and it seems that whoever played with whom.

Wrong! There is a hidden condition here, "three people agree to rest in the next sentence of each game loser" This sentence shows that there are no two consecutive games played by two of the same people, and then go back to look at the data we listed, pay attention to Xiao Qian and Xiao Zhao played 6 rounds, a total of 11 rounds, to make 6 rounds not consecutive, only 1,3,5,7,9,11 rounds are played by Xiao Qian and Xiao Zhao.

Zhao rested for 2 rounds. Then: Qian played 2 games with Sun.

Money played 8 rounds. Then: Qian played 2 games with Sun, and Qian played 6 rounds with Zhao.

Sun played 5 rounds. Then: Sun played 2 games with Qian, and Sun played 3 rounds with Zhao.

To sum up: a total of 11 rounds. They are 2 games of Qian Sun, 3 rounds of Sun Zhao, and 6 rounds of Zhao Qian.

And: Two adjacent innings cannot be the same two people.

Then: Zhao Qian's 6 rounds can only be arranged in these 6 rounds.

The rest are arranged at will. That is: the odd number of items must be Zhao Qian. Select B

The language used for analysis can be a bit more complicated to make it easier for you to understand. When you actually do it, it takes about a minute.

Correct answer: B

Analysis: Xiao Zhao rested 2 games, that is, Xiao Qian and Xiao Sun played 2 rounds, then Xiao Qian and Xiao Zhao played 8-2 = 6 rounds, Xiao Sun and Xiao Zhao played 5-2 = 3 rounds, then a total of 2 + 6 + 3 = 11 rounds, so Xiao Sun rested 6 rounds in 11 rounds and played 5 rounds, because it is impossible to rest 2 games in a row, so Xiao Sun must have rested 1 game to play 1 game ......, so in the 9th game, Xiao Sun rested, Xiao Zhao and Xiao Qian played.

4-1) x2

3x26 (field).

A: Every 2 students have to play a total of 6 games.

4 (4-1) Opened 2

6 (games) Answer: A total of 6 games will be played by Natong

So the answer is Min Ran: 6

Ideas: Xiao Zhao rested for 2 rounds, which means that there were only 2 games between Xiao Qian and Xiao Sun, so Xiao Qian and Xiao Zhao compared 6 rounds, and Xiao Sun and Xiao Zhao compared 3 rounds, so Xiao Zhao played 9 rounds, plus Xiao Zhao rested for 2 rounds, you can know that the game went on for 11 rounds, so Xiao Qian rested for 3 rounds, and Xiao Sun rested for 6 rounds. According to the above calculations, one of the people who can participate in the 9th game must be Xiao Zhao.

And Xiao Sun only played 5 rounds, so Xiao Sun could not participate in the 9th game.

Answer: aXiao Zhao and Xiao Qian.

There were 2 games of less than the game, which were against Xiao Zhang and Xiao Wang.

Analysis: (1) Key points: There are 5 classmates, Xiao Zhang has played 4 games, Xiao Zhang can't compete with himself, so he can only play 4 games at most. From this, Xiao Zhang and all his classmates played 1 game.

2) Key point: Xiao Zhao played 1 game, combined with (1), it was learned that Xiao Zhao only played 1 game with Xiao Zhang.

3) Key point: Xiao Wang played 3 games. Combined with (2), it was learned that Xiao Wang did not play with Xiao Zhao, so Xiao Wang and Xiao Zhang, Xiao Gao, and Xiao Xiao each played 1 game.

4) Key point: Xiao Gao played 2 games. Combined with the above points, it is known that the two games of Xiao Gao's competition are with Xiao Zhang and Xiao Wang.

Therefore, there were a total of 2 games for less than one, which were against Xiao Zhang and Xiao Wang. (Ask).

（10×9）÷2

45 (games) A: A total of 45 matches will be played

So the answer is: 45

It seems like 45 games to play.

What does the landlord want to do? If you want to divide into 1, 2, and 3, it is recommended to divide into three or four groups, and the group cycles.

For example, if there are three groups with 4, 3, 3 players, the first stage of the cycle is 6, 3, 3 respectively, and then consider the next stage of the game, so the number of games is a little less.

If you're serious, take a look at the rules of the contest.

According to the title, there should be a total of 31 games.

The first level of games should be 16 games, and then halved in turn, so that the total number of games is 16*2-1=31.

Please refer to it, thank you!

A total of 31 matches are played, with 15 matches played in each group, with the last match played by the two group winners.

The question should be a total of 31 games.

Because A and B have 16 players each, it takes 15 games to determine the first place in each group of single-elimination matches. The two groups need to be multiplied by two, and the group stage needs 30 games. But the problem is that the last two groups of winners will play in the finals, so there is also a final final.

So I personally think it's going to take 31 games.

In the end, the two teams won the game 1-0 and won the gold medal.

But this can be used to use the equation, only the stove will be table tennis x people, only badminton y people, will z people, then.

x+y+z=40 1

x+z=25 2

y+z=20 3

2+3-1 i.e. (x+y+2z-(x+y+z))=5. 5 people.