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1、(7+4m)(7-4m)
2. (Quarters of the Y square + quarters of the Y square.)
3、(4x+1)(4x-1)
4. A b(b+2)(b-2), squared form (5, xy-9x 3y=xy(1-y 2)=xy(1+y)(1-y)6, a 3[x+y] -4a 3c = a 3([x+y] -4c )=a 3(x+y+2c)(x+y-2c).
a²[x-y]+b²[y-x] =[x-y](4a²-b²)=[x-y](2a+b)(2a-b)
a-b]²-a+b]²=[2(a-b)]²a+b]²=(3a-b)(a-3b)
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1.(x-y+z) - (x-y-z) = [ x - y + z) +x - y - z) ]x - y + z) -x - y - z)].
2x - 2y) *2z
4z(x - y)
2.a- (5th power of a).
a (a^4 - 1)
a (a² +1)(a² -1)= -a(a + 1)(a - 1)(a² +1)3.16 (a-b) + (b-a) to the 3rd power.
a - b) [16 - a - b)² = (a - b) [4² -a - b)² = (a - b) (4 + a - b)(4 - a + b)4 .x squared - y squared + (x+y).
x + y) (x - y) +x + y) = (x + y) (x - y + 1) 5 questions are missing a + sign.
5.2a(m-n) to the 3rd power + 2a to the third power (n-m) = 2a(m-n) [m-n) 2a)] = 2a (m - n)(m - n + 2a)(m - n - 2a)
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1: Original formula = (x-y+z+x-y-z)*[x-y+z-(x-y-z)]=(2x-2y)*2z
2: Original formula = a(1-a 4) = a(1+a 2) (1-a 2) = a(1+a 2) (1+a)(1-a).
3: Original formula = (a-b)[16-(a-b) 2]=(a-b)(4+a-b)(4-a+b).
4: Original formula = (x+y)(x-y)+(x+y)=(x+y)(x-y+1)5 The meaning of the question is unclear.
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1 original = 2a (4a 2-1) = 2a (2a + 1) (2a-1) 2 original formula = 3abc (9a 2-b 2) = 3abc (3a + b) (3a-b).
3 original = 5 (a 2-4b 2) = 5 (a + 2b ) (a - 2b) 4 original = ((2n + 1) + (2n - 1) (2n + 1) - (2n - 1) ) = (4n ) (2) = 8n
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-a to the fifth power + a
A-A to the fifth power.
a (1-a to the fourth power).
a (1-a quadratic) (1+a quadratic).
a(1-a)(1+a)(1+a) (1+a) 3 [m+n] 2 to the 2nd power -27n to the power.
3 ([m+n] 2nd power - (3n) to the second power) = 3 (m+n+3n) (m+n-3n).
3(m+4n)(m-2n)
25x101 to the second — 99 to the second to 25
25 (101 to the second of 99).
The power of a is [a-b] + the power of b [b-a] = the power of a [a-b] - the power of b [a-b] = (a-b) (the power of a - the power of b).
a-b)(a-b)(a+b)
a-b).
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Are you sure you wrote it right, I think math is great and can help you.
1.-2b
2.Question 2: No. >>>More
1.(x+2)(x-2)
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Observing these four problems, they all use the square difference formula to defactor the factor to solve the one-dimensional quadratic equation drop, mainly using a -b = (a+b)(a-b). >>>More
The first question takes the minimum value when a=2 and b=1, the second question = 3 to the 16th power, the third question has a side length of 5, and the fourth question = -1, I am a sky walker