A few unary quadratic equation application problems. Matching method. Solving.

Updated on educate 2024-04-25
15 answers
  1. Anonymous users2024-02-08

    1.Solution: Let the width of the horizontal color bar be xcm, then the width of the vertical color bar is 32x, and the area of a horizontal color bar can be seen from the figure:

    x 20, the area of a vertical color bar is: 32x 30, there are four overlapping parts, the overlapping area is: x 32x 4, because the area of all color bars is one-third of the total area, so the column equation is:

    2 x 20+2 32x 30-x 32x 4= 13 20 30, solution: x1 = 53, x2 = 20 (twice greater than 30, rounded), should be designed horizontal color bar width of 53cm, vertical color bar width of.

    2.Solution: (1) If the length AB of the enclosed rectangular ABCD is X meters, then the width of the AD is 12 (80-X) meters

    According to the title, x 12 (80-x) = 750

    That is, x2-80x+1500=0, solve this equation to get x1=30, x2=50

    The length of the wall should not exceed 45m, x2=50 is not in line with the topic and should be discarded

    When x=30, 12(80-x)=12(80-30)=25, so when the length of the enclosed rectangle is 30m and the width is 25m, the area of the rectangle can be 750m2

    2) No, because x12 (80-x) = 810 gives x2-80x + 1620 = 0

    and b2-4ac=(-80)2-4 1 1620=-80 0, and the above equation has no real roots

    Therefore, it is not possible to make the area of the enclosed rectangular site 810 m2

    3.(1) From the title, 400 (2x + 400x) + 300 400x + 200 80 = 47200

    That is, 800x+ 400 700x+200 80=47200

    Simplification yields x2-39x+350=0

    The solution is x=14, x=25

    It is tested that it is the solution of the original equation, but x=25 16 (discarded if it does not fit the topic).

    So when the total cost of the pool is 47,200 yuan, the pool is 14 meters long

  2. Anonymous users2024-02-07

    2.(1) The wall can use x m, x*(80-x) 2=750, that is, x 2-80x=1500, x=50 x=30Find the area of 750 when the wall is 30m

    2) x*(80-x) 2=810, no solution.

  3. Anonymous users2024-02-06

    Question 2: (1) How to make the area 750 m 2 The length of the strong side is 15 meters.

    2) Can the area of the rectangular field be 810m2 No.

  4. Anonymous users2024-02-05

    The method of Founder is as follows, please refer to it in large and rough:

    If it helps, please take a nap.

  5. Anonymous users2024-02-04

    In general, there is a field positive formula for the solution of a quadratic equation, and there is also a formula that can be factored.

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  6. Anonymous users2024-02-03

    This diagram examines binary equations.

    Let the single digit be x and the ten digit be y

    The title can be listed as:

    x+y=14①

    10y+x-18=10x+y②

    Simplification to 9y-9x=18

    y-x=2③

    2y=16

    y=8 substitutes y=8 into .

    x+8=14

    x=6A: The original single digit is 6, and the ten digit is 8

  7. Anonymous users2024-02-02

    AX, BY, C, 50-x-y

    1500x + 2100 + 2500*(50-x-y)= 90000

    Finishing up to 10x + 4y = 350

    x and y are both integers, and substituting them to satisfy the above equation, and x + y < 50 meet the above conditions of the three sets of data are the three sets of schemes.

  8. Anonymous users2024-02-01

    Price increase in this case:

    Let the average percentage of the price increase be x, then: the current ** = original ** number type (1 + x) number of price increases.

    Price increase this Heng Brother Situation:

    Let the average percentage of price increase be x, then: now**=original** (1-x) number of price reductions.

  9. Anonymous users2024-01-31

    Set a price reduction of x percent each time

    300 (1-hundredth x) 2 = 243 to unravel.

  10. Anonymous users2024-01-30

    Price increase in this case:

    Let the average price increase percentage be x, then: current price cong faction = original ** (1+x) number of price increases.

    Price increase in this case:

    Set the average percentage of price increase to x, and dismantle Zheng Hui.

    Then: now**=original** (1-x) is reduced to x300 (1-hundredth x) 2=243 for each price reduction.

  11. Anonymous users2024-01-29

    Analysis: In this problem, the average percentage of each price reduction is x, then the drug price is yuan after the first price reduction, and the second time it is reduced by x on the basis of the yuan, and it becomes the yuan, and then the equation can be listed to find the answer Answer: Solution:

    Let the average percentage of each price reduction be x, then the ** after the second price reduction is yuan, according to the title:

    i.e. (1-x)2=

    Solution, x1 = (rounded), x2 =

    So the average percentage of each price reduction is, ie.

  12. Anonymous users2024-01-28

    Total price reduction: yuan).

    Percentage of total decline:

    Average percentage of each drop:

  13. Anonymous users2024-01-27

    Set the width to x meters.

    then a+2x=35 1).

    ax=150 2)

    From equation (2): a=150 x

    x2=10,a=15

    Because a is greater than or equal to 20m, so x2=10 is not in line with the topic, so the length of the chicken farm is 20 meters, and the width is meters.

  14. Anonymous users2024-01-26

    If the width of the chicken farm is xm, the length is (35-2x)m and the equation is x(35-2x)=150

    Finishing, get 2x2-35x+150=0

    Solve the equation to get x1=10, x2=

    So when x=10, 35-2x=15;

    When x=, 35-2x=20

    Therefore, when the width of the chicken farm is 10m, the length is 15m; When the chicken farm is wide and 20m long, I'm doing a task, if this answer is okay, you can help set it up to a satisfactory answer, thank you, help.

  15. Anonymous users2024-01-25

    Solution: If the chicken farm is x meters long, it will be (35-x) 2 meters wide.

    x*(35-x)/2=150

    x^2-35x+300=0x=

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