Ask a few 6th grade math Olympiad questions to be fast

Question 1: 19 30 (19/30).

Question 2: 4 7 (4/7).

Question 3: 6 11 (6/11).

Question 4: 18

Question 5: 1 3 (1/3).

Question 6: 7 12 (7/12).

Question VII: 14

Question 8: 24 5 (24/5).

Question 9: 5 12 (5/12).

I've verified the answers, absolutely no problem!

1.19 30 (19/30).

2.4 7 (4 out of 7).

3.6 11 (6 out of 11).

5.1 3 (1/3).

6 7 12 (7 out of 12).

7.The denominator is added by 14

8.9 2 (9 out of 2).

9 5 12 (5 out of 12).

I'll keep it, just come to me if you have a problem.

I'll just give you that.

It's very simple, but to point the time, don't do it!

Question 1: 19 30

Question 2: 7 12

Question 3: 6 11

Question 4: 185 Question: 1 5

Question 6: 7 12

Question 7: 148: Question 9: 5 12

Question 6 is not copied wrong, the landlord will give points, there is a problem.

Now the Olympiad is so simple.

Write the rest downstairs.

It can be solved with a system of binary linear equations or fractional equations.

Let's do it yourself, don't wait for others to give you an answer.

Answer: 1 question. 19 30 2 questions. 4 7 3 questions. 6 11 4 questions. 18 5 questions. 1/3

6 questions. 7/12

7 questions. 14 8 questions. 6 9 questions. 5/12

1 Let the fraction be x yAccording to the meaning of the question, x+5 y=4, and 5x+25= solution x=, then the score is 19 30And so on, and the following questions are easy to do.

2 questions are 4 7....Don't wait for someone else to tell you...

Dear, please send the original question**Yo? The teacher will answer in detail! Thank you ha! <> received. (2) It's not very clear, and it's troublesome to analyze.

That's all the first question.

Okay, go ahead and write by hand.

This question has caught up with a big question in junior high school.

Indeed it is. Okay, thank you.

Give you a <> of thumbs up

<>Uh-huh.

Suppose the part of the shorter stake that originally outcrops the water surface a centimeter.

10a+20):(a+20)=5:2

2*(10a+20)=(a+20)*5

A=4A: Yes 4 cm.

Set to x to have a long length of 10x

There is a drop in the 20s.

10x+20）：5=（x+20）：2

So x=4

If the long wood falls 20 cm.

Short wood water surface drop 20 10 = 2 cm.

Then the length ratio of the outcropping is still 10:1

Now the length of the short wood is 20-2=18 centimeters, and the ratio is 5:2=10:4

Now the length of the short log outcropping out of the water is:

18 (4-1) 4=24 cm.

It turns out that the length of the short wood outcropping from the water is: 24-20 = 4 cm.

Since the length and width are equal to half the height, the six sides of this box are two squares and four rectangles. A rectangle is exactly two squares put together.

Then, the original surface area is 4*2+2 squares.

For each horizontal cut, add two rectangular areas, i.e. the area of 4 squares.

Each vertical cut increases the area of the two squares.

Then, after cutting, the surface area is increased by a total of 8+6 squares, that is, 4*2+2+8+6=24 squares.

The area of 24 squares is equal to 600dm 2 and the area of each square is 600 24 = 25, then the length, width and height of the original cuboid are 5 5 10

The volume is 250

Suppose the length is 2x, the width x, and the height x

The surface area of horizontal cutting 2 knives is increased by 4*2x*x on the basis of the previous one, and the surface area of vertical cutting 3 knives is increased by 6*x*x

So the total surface area: s=2*2x*x+2*x*x+2*2x*x+4*2x*x+6*x*x=600

Solution: x=5

The volume of the box is: 2x*x*x=250

Dude, assuming that the width and height are a, then the length is 2a. You can think of two ways to cut and the result is different; If you think about it, you will see that the surface area increased by the 12 small cuboids is the cut of the knife.

The surface area of the original cuboid was calculated to be 10a

If you cut the length with two knives and cut the width with one cut, and increase the surface area to 4 wide and high surfaces and 2 long and wide surfaces = 8a, then 18a = 600 to find a.

If you cut two knives wide and one knife long, then add 10a, that is, 20a = 600 to calculate a.

The square of the height * the square of the width * the square of the length = 61,200 square decimeters.

Set the width to x

Box surface area = 2 (x 2 * x 3 + x 3 * x + x 2 * x) = 600 x = 300

The volume of the box = 2 (2*x*2x+x) = 10x = 3000

Let width = height = 6x, then the length is 12x, and the width of the cut cuboid = 6x, height = 2x, length = 3x, s = (3x*6x+3x*2x+2x*6x)*2*12=600

x=5 6, so d=h=5, l=10, v=5*5*10=250

1.Set the speed of the escalator to x. Then the distance that the two of them took to move the air should be the same.

Equation: (20+x)5=(15+x)6 gives x=10, so the number of steps is: (20+10)5=150 steps.

2.A and B have two ships, one is downstream and the other is countercurrent. Then let the speed of the still water ship x, so that one of the speeds (x+6) and one (x-6).

When they meet in 4 hours, the distance traveled by the two sides is (x+6)4, (x-6)4, and the difference distance is (x+6)4-(x-6)4=48 kilometers.