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The first space: the current of the series circuit is equal everywhere: i 3 r1 = the second space: r2 voltage is: , the power supply voltage: 3 + 2 5v the third space: 4 + 6 10 ohms.
First empty: 9-3 6 euros.
The second space: the current is equal everywhere, i 9v 9 ohm 1a third space: u 1a * 6 ohm 6v
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.If they are connected in series to both ends of a circuit, and the voltage at both ends of R1 is measured by a voltmeter to be 3V, then the current flowing through the resistor R2 is 3 6 = and the supply voltage is , and the total resistance of the circuit is 6 + 4 = 10 ohms.
Resistors R1 and R2 are connected in series to a power supply with a voltage of 9V, the resistance R1 = 3 ohms, the total resistance of the circuit is 9 ohms, then the resistance R2 = 9-3 = 6 ohms, the current through R1 is 9 9=1 A, and the voltage at both ends of R2 is 1*6=6 V.
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The current of the series circuit is equal everywhere, i total = i1 = i2
1) R2 current = 3 volts 6 ohms = , power supply voltage ampere*10 ohms = 5 volts total resistance 10 ohms.
2) r2 = 9 ohms - 3 ohms = 6 ohms r1 current is 9 volts 9 ohms = 1 amp r2 voltage is 1 amp * 6 ohms = 6 volts.
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Balances and rod scales are both tools for measuring the mass of an object, and they are both made according to the principle of lever balance, the difference is that the balance is an equal-arm lever, while the two arms of the rod scale are not equal.
Trust me, you can't go wrong.
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Weights, levers, equal arms, etc.
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The mass of the lever balance and the equal arm lever are not equal.
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1. Increase the stress area and reduce the pressure.
2. Reduce pressure and pressure; Increase the stress area and reduce the pressure.
3. Reduce the stress area and increase the pressure.
This is the correct answer.
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1: Increase the pressure, increase the force area 2: reduce the pressure, reduce the pressure, increase the force area 3: increase the pressure, reduce the force area.
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The average velocity of the two segments is the same, v1 = v2
And because t=v a, t1 t2=a2 a1, t1=t2a2 a1 is substituted into t1t1a1 2 + t2t2a2 2=s (with average velocity) to solve.
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It is known that the boiling points of liquid oxygen, liquid nitrogen and liquid carbon dioxide are -183, -196 and -78 respectively
The method of cooling is adopted to liquefy the air, the temperature gradually decreases, when it drops to -78, the carbon dioxide is first liquefied and separated, and the temperature continues to drop, when it drops to -183, the oxygen liquefaction is separated, and the temperature continues to drop, and when it drops to -196, the nitrogen liquefaction is separated.
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1) Pull the rubber at a constant speed.
2) W has =gh=2n 0 1m=0 2j
w total = fs = 0 file such as know 8n 0 4m = 0 32j = w has w total = 0 2j 0 32j = 62 5%.
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The attraction of the Moon to objects is only one-sixth that of the Earth, and the lunar soil will loosen the bridge compared to the soil on the Earth.
According to the knowledge of friction, the friction between the lunar rover and the lunar soil is smaller, so the surface of the wheels should be rough
After investigation, the astronaut who landed on the moon was a hand-closed sports enthusiast, who could lift a 60kg barbell on the earth and pull 5 springs of a certain brand of tension device; On the moon, he can lift a 360kg barbell without pulling 30 springs of the same brand of tension (both blanks are optional). Yes. Or.
No) Min Potato Min.
1) Process Indicates that the colorless solution is acidic. >>>More
You can go buy a book on physics. For example, the talent is worth it. Do it. There are answers later. And the rolls. It's not very expensive either.
One. 1.The work done by gravity is equal to the amount of change in gravitational potential energy. The direction of gravity is the same as the direction of the ball's motion, doing positive work, w=gh=mgl >>>More
This. Isn't that a special case of the first law of thermodynamics? >>>More
These are annoying. It's the foundation + the foundation + the foundation + the workaround = the answer. So it's still necessary to do more questions. Look at the formula. That's all,