Chemical symbolic expression of the combustion reaction of the three gases H2CO CH4

2h2 + o2 === 2h2o

2co + o2 === 2co2

CH4 + 2O2 === CO2 + 2H2O Identification: Ignite separately, invert a small dry beaker above the flame, no water droplets are CO, and there are water droplets H2 and CH4. These two, lit, and then inverted a small beaker coated with clarified lime water, there is a turbidity phenomenon is CH4.

Ignite the top cover, cover a dry cold beaker, and the water beads are CO 2CO+O2=2CO2, and the lime water does not become turbid, it is H2 H2+O2=2H2O, both of which have changed, and it is CH4 2CH4+3O2=CO2+4H2O, and the answer to the second question is C

Carbon monoxide and hydrogen** do not explain that flour can be dusty**.

If you want to know the specific division into **, tell me.

When H2 is impure, there will be a popping sound when ignited.

CO is a toxic gas that is reducible and reacts with oxygen to form CO2

CH4 is the simplest organic matter that reacts with oxygen to produce water and carbon dioxide, commonly known as biogas.

2h2+o2=2h2o

2co+o2=2co2

ch4+2o2=co2+2h2o

ps Burning symbol add it yourself)

Three combustion products over lime water, the difference goes to H2

Then supercondense the tube, distinguishing between C0 and CH4

1.Literal expression: hydrogen + oxygen - ignition water.

Chemical equation: 2H2 + O2 = Ignition = 2H2O

2.Literal expression: copper + oxygen - heating copper oxide.

Chemical equation: 2Cu + O2 = Heating = 2CuO

2H2 O2 ignites 2H2O

Hydrogen and oxygen ignite water.

The ratio of CH4 to complete combustion to produce gas is exactly 1:2, so it is uncertain whether there is or not, B is correct.

Both CO and H2 are completely burned to produce only one gas, so if there is CO, there must be H2 C, which is correct.

d is also correct according to the proportional relationship.

So it's not the right choice A

2CO + O2 ==2CO22H2 + O2 (Ignition Scattering Smoldering) ==2H2OCH4 + 2O2 (Spot Grip and Ignition) ==CO22H2O

The equation of CO2, H2O and Na2O2 reaction is tricky for many students, and it is basically written by rote memorization, but the good times are short-lived, and they will soon forget! So what to do? Teacher Qianlong created an original method to share with dear students, welcome students to be serious!

a. In the reaction, "+" is read as "and", and the reaction can be read as: methane and oxygen react to produce carbon dioxide and water under ignition conditions, so the option is read incorrectly

b. The reaction cannot be read as 1 methane and 2 oxygen under ignition conditions to produce 1 carbon dioxide and 2 water; Microscopically, 1 CH4 molecule and 2 O2 molecules generate 1 CO2 molecule and 2 H2O molecules under ignition conditions, so the option is read incorrectly

c. Microscopically, 1 CH4 molecule and 2 O2 molecules generate 1 CO2 molecule and 2 H2O molecules under ignition conditions, so the option reading is correct

d. The reaction can be read as: every 16 parts of methane and 64 parts of oxygen react under ignition conditions to produce 44 parts of carbon dioxide and 36 parts of water, then 1GCH4 and 4Go2 can fully react under ignition conditions, so the option reading is wrong

Therefore, C