If the middle lines on the two straight sides of a right angled triangle are 5 cm and 2 cm respectiv

Let the two right-angled edges be a and b respectively

According to the Pythagorean theorem:

a^2+(b/2)^2=5^2...1)

a/2)^2+b^2=2^2...2)

Add the two formulas: 5 4 (a 2 + b 2) = 5 2 + 2 2, a 2 + b 2 = 4 5 * (5 2 + 2 2) = 116 5 ...3）

Subtract from the two formulas: 3 4 (a 2-b 2) = 5 2-2 2, a 2-b 2 = 4 3 * (5 2-2 2) = 28 ...4）

3）-（4）：2b^2=116/5-28=-24/5＜0

Does not form a triangle, wrong question.

Change the title to: [The middle line on the two right-angled sides of a right-angled triangle is known to be 5cm and 2 times the root number 10cm respectively to find the length of the hypotenuse].

Let the two right-angled edges be a and b respectively

According to the Pythagorean theorem:

a^2+(b/2)^2=5^2...1)

a/2)^2+b^2=(2√10)^2...2)

Add the two formulas: 5 4 (a 2 + b 2) = 5 2 + (2 10) 2

a^2+b^2 = 4/5*[5^2+(2√10)^2] = 4/5*65 = 52

Hypotenuse = 52 = 2 13

wqqts |Level 16 considerations are deep-seated and beyond the reach of ordinary people. Inspired by this, I found this explanation:

a + b 2 = 4, i.e. a 4 + b 16 = 1, can be regarded as the standard equation of an ellipse;

b + a 4 = 25 i.e. a 100 + b 25 = 1, which can also be regarded as the standard equation of an ellipse;

The two ellipses are mutually contained, and there is no common point, so such a a and a b do not exist.

But this explanation is incomprehensible to junior high school students.

Solution: Let the right-angled edges be a and b respectively, and the hypotenuse side is c

From what is known:

a^2 + b/2)^2 = 52

a/2)^2 + b^2 = 22

Add the two formulas, and the solution is obtained:

a^2+b^2=116/5

Obtained by C2 = A2 + B2:

c 2 = 116 5, i.e. hypotenuse c = 2 145 5

Thirty-five under the root number of two-fifths.

Problem solving ideas: Use the Pythagorean theorem to find the length of the hypotenuse, and then solve the solution according to the middle line on the hypotenuse of the right-angled three-volt simple angle hypotenuse

According to the Pythagorean theorem, hypotenuse =

82 + 152 = 17cm, therefore, the length of the midline on the hypotenuse = [1 2] 17 = so the answer is: 1,

The middle line on the hypotenuse is half of the Kishi with the length of the hypotenuse.

So the bevel is 12cm long.

The area of the pulsed limb is 1 2 * 5 * 12 = 30 cm 2

The length of the midline on the hypotenuse of the right triangle.

cm

13 According to the Pythagorean theorem, hypotenuse length = root number (5 2 + 12 2) = 13 , give a take, thanks!

6 or hypotenuse may be 12 or 13

Hypotenuse = root number (10 2 + 5 2) = 5 root number 5

Because the middle line on the hypotenuse of a right triangle is equal to half of the hypotenuse.

So the middle line on the hypotenuse = (1 2) * hypotenuse = (5 root number 5) 2 The side length of the square is root number 27 = 3 root number 3

If you have any questions, you can ask me.

The hypotenuse is (100+25)=5 5

The midline of the hypotenuse is 5 5 2

The area of the square is 27

Then the side length is 3 3

The length of a right-angled side of a right-angled triangle is 3cm, and the length of the middle line on the hypotenuse is , then the length of the hypotenuse = 2*cm.

So, the other right-angled side length is: root number (5 2-3 2) = 4 cm.

So, area = 1 2 * 3 * 4 = 6 square centimeters.

The length of the middle line on the hypotenuse of a right triangle is So the hypotenuse is 5 and the other side = 4 so area = 6

The hypotenuse is long, so the length of the two right-angled sides is 3cm and 4cm respectively

The area is 3 4 2 = 6cm

Hypotenuse = root number (164) =

The length of the midline on the hypotenuse =

The hypotenuse length is 64+100 = 2 41

The midline of the hypotenuse = half of the hypotenuse = 41

When 10cm is the hypotenuse, the answer is 5cm

The middle line of the hypotenuse of a right triangle is equal to half of the hypotenuse ......The hypotenuse is 6cm long

According to the median line theorem, the length of the line connecting the midpoints of two right-angled edges is exactly equal to half the ...... of the hypotenuseSo the length of the connection is equal to 3cm

The hypotenuse midline is half of the hypotenuse, and the midpoint line is the median line and the hypotenuse is half.

Solution: 4cm reason, the length of the closed hole line on the hypotenuse of the right-angled triangular celery manuscript is equal to one and a half of the hypotenuse. The length of the line connecting the midpoints of the two right-angled edges is also equal to half the length of the hypotenuse.