How to do the last question of P114 in the 6th grade math class? 5

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3/20 decimal fraction 4/5 11/10

Percentages 15 40 80 110

I don't do this thing, you can ask the teacher.

Hello! Please type out the question! Thank you! Laugh at it!

What is the topic, I don't have a book in my hand.

The first type: 120 times 25% of coal burned per day divided by 8 =, the total time divided by 120 days;

The denominator of a fraction that can be reduced to a finite decimal is that there are no other factors other than 2 and 5.

Therefore, within 100, all numbers containing only factors as the denominator meet the requirements of the topic, specifically:

First find the left part of the shadow, and the left shadow plus the surface triangle is 1 4 circles.

That is, 6cm is the radius of the circle.

1 4 The area of the circle minus the area of the triangle above is the area of the left shadow, and the right shadow is so simple.

S shadow = area of a large right triangle + sector area + area of a small square - area of a small square - area of a large square.

1 2 times (6 + 4) times 6 + 90 times 6 times 6 360 + 4 times 4-4 times 4-6 times 6

9π-6（cm2）

First make the auxiliary line on the right, get a rectangle with a length of 10 cm and a width of 6 cm, find the area of a quarter circle and the area of a rectangle with a length of 6 cm and a width of 4 cm, and then subtract the area of the triangle with a length of 10 cm and a height of 6 cm to get the shaded part.

Make an auxiliary line, connect the diagonal of the large square (the shaded part), divide the shaded part into a triangle and a bow, the triangle area is, the bow area is 6, and the two areas can be added.

The actual length of the playground: 24 * 1000 = 24000 cm = 240 meters.

Actual width: 18 * 1000 = 18000 cm = 180 meters.

Actual perimeter: (240 + 180) * 2 = 840 meters.

Looking for this**, it's okay, I'm lazy and don't want to write.

Set the base area to x

So x=(5*6*8) 5*3

144dm2

or x*(1 3)*5=5*6*8

Solution x=144

Solution: It can be known from known conditions:

v (rectangle) = 8 6 5

240dm3

v (rectangle) = v (cone).

s (cone base area) 5 1 3 = 240

s (cone base area) 5=720

s (cone base area) = 144dm2

Let the bottom area of the cone be xdm

8*6*5=1/3*5x

x=144

8x6x5÷(1/3)÷5=144

The equation may be better understood.

Let the bottom area be s, and get:

5s/3=8x6x5

Got s 144