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It was observed that from the first term, each number is an ordinal number squared, and the number at the position of the even ordinal number is (-1).

So get the general formula.

n (1) to the power of (n+1).

When n = 1, 1 1) to the power (1+1) = 1, when n = 4, 4 1) to the power (4+1) = -16, from which we can see. When n = 100, 100 1) to the power of (100+1) = -10000 is solved.

The first number is [(-1) 0] 1 2=1

The second number is [(-1) 1] 2 2=-4

The third number is [(-1) 2] 3 2=9

The nth number is [(-1) (n-1)] n 2, so the 100th number is [(-1) 100] 100 2=-10000

1:1 squared.

4:- (2 squared).

9:3 squared.

16:- (4 squared).

25:5 squared.

When the odd number: the square of the number of the first terms, such as the 7th: 7*7 even number: - (the square of the number of the first terms), such as the 8th: - (8*8) the 100th: is the even number: - (100*100) = -10000

Odd squared. Even numbers squared plus a minus sign.

In the above question is "1, 2, 3, 4, 5....of the squared.

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Solution: 1. Original formula = (20102009 +1) [20102008 +(20102008+2)].

20102009²+1)/(20102008²+20102008²+2x20102008+4)

20102009 +1) 2(20102009 +1) [Merge similar terms, extract common factor].

2. Original formula = (1+1 2) (1-1 2) (1+1 3) (1-1 3) (1+1 4) (1-1 4) .1+1/n)（1-1/n)

3/2 * 1/2 *4/3 *2/3...n+1)/n *(n+1)/n

n+1)/n

(1) Simplification:

5x to the power of 4 3x y 10 3x y x to the power of 4 = (5x x) 3x y 3x y) 10 = 6x -10

2) Simplify and evaluate:

2(a2) 3(1 1/3a).

2a+4-3+a

2a+a+4-3

3a+13x(-2)+1

(1) 5x to the power of 4 3x y 10 3x y x to the power of 4 = (3x y 3x y) - 10 = 626 * (x to the power of 4) - 10

2) 2 (a 2) 3 (1 1/3a) = 2a + 4-3 + a = 3a + 1, because a = -2, so = 3a + 1 = 3 * (-2) + 1 = -5