Math problem, this problem appears in a one dimensional inequality, please be careful.

1) Set up a type A washing machine x sets.

500x+1000(80-x)=61000x=38 units.

B type washing machine 80-38 42 sets.

2) Set up a type A washing machine x sets.

5200<=(550-500)x+（1080－1000)(80-x)<=5260

5200<=50x+80*80-80x<=52601200<=-30x<=-1140

38<=x<=40 units.

40 to 42 washing machines of type B.

1.Solution: Set X units of model A and 80-x units of model B.

500x+1000(80-x)=61000500x+80000-1000x=61000500x=-19000

X=38A: 38 units of model A, 42 units of model B.

2.Solution: Set X units of model A and 80-x units of model B.

550-500）x+(1080-1000)(80-x)≥5200——550-500）x+（1080-1000）（80-x）≤5260——②

Yes 50x+80*80-80*x 520030x -1200

x 40 has 50x+80*80-80*x 526030x -1140

x 38 So the solution of this equation is 38 x 40 Answer: Scheme 1: 38 units of model A and 42 units of model B.

Scheme 2: 39 units of model A and 41 units of model B.

Scheme 3: 40 units of model A and 40 units of model B.

If you think it's good, choose me.

If you still have any questions, please feel free to ask me (*

The speed of 3 kilometers is 1 3 hours, 20 minutes, and the distance you need to walk is 10-1=9 kilometers.

11:00-9:50=70 minutes.

Subtracting the time to enter the station and check in the ticket for 20 minutes and the 20 minutes to walk, it takes at least 70-20-20 = 30 minutes to get on the train at 11 o'clock, that is, hours.

If the bus travels x kilometers per hour, there is.

So x 18

This means that the bus travels at least 18 kilometers per hour on average to be on track.

There are 70 minutes in total, minus 20, it is 50 minutes, 20 minutes on foot, and there are 30 minutes left to walk 10-1=9 kilometers, that is, the bus travels at least 18 kilometers per hour on average to stay on track.

It's very simple, 11:00-9:50 = 70 minutes, 70-20 = 50 minutes, 1 3 = 1 3 hours = 1 3 * 60 minutes = 20 minutes, 50-20 = 30 minutes = hours, 10-1 = 9 kilometers, 9 kilometers, so at least 18 kilometers per hour to not miss the train.

Do you understand?

Solution: The average bus travels at least x kilometers per hour to avoid the mistake of the train.

11:00-9:50=70min 70-20=50min50-1/3*60=30min=

So" = 9x> = 18

A: On average, buses travel at least 18 kilometers per hour to stay on track.

Walked for 1 3 hours, 20 minutes = 1 3 hours.

11 a.m. - 10:50 = 70 p.m. = 4 3 p.m.

4 3-1 3-1 3=1 2.

Solution: Set at least x kilometers for an hour to avoid missing the train.

1/2x>=10-1

x>= 18

A: At least 18 kilometers per hour.

If there are x workers, you can get 10x>10*20*, that is, 10x>160, that is, x>16, so there are at least 16 people.

There are x people at the construction site, 10*20*<10*x condition x<20 solution x>16

Then 16 is the multiplier sign.

Solution: If there are x 10 yuan banknotes, then there are (60-x) 50 yuan banknotes, and 10x+50 (60-x) 2000 according to the title

Solve this inequality, got.

x 25x is an integer, and x is the smallest is 26

A: He owns at least 26 $10 notes.

The speed of the vehicle is at least xkm h

20/60）x=4*(3+20/60)

1/3x=40/3

x = 40 B at least 40 km h

1. If there is a minimum of x 10 yuan, then 50 yuan is 60-x 10x + 50 (60-x) 200010x + 3000 - 50x 200040x 1000

x ≥ 25

2. Set the minimum speed to x kilometers per hour.

3×4 ≤ 20x/60

x/3≥ 12

x 36 A: At least 36km h

Autumn Wind Yanyan answers the question o( o 】

If you don't understand anything, you can continue to ask this question.

If you are satisfied, please select the satisfactory answer in time, thank you.

1...10x+50 (60-x)<2000 -40x<-100040 x>1000 x>25 at least 26 sheets.

2...Let B's speed be x, and remember to turn 20 minutes into 1 3 hours.

4*3) (x-4)=1 3, find x as x=40

1: Set up to x sheets.

60*10+50x＜2000

50x＜28

A: You can have up to 28 tickets.

2: Set at least x kilometers per hour.

1/3x＞4*3

1) Solution: Set at least x 10 yuan yuan.

10x+3000—50x<2000

40x<-1000

x>25

A: At least 26 tickets of 10 RMB.

2) 20 minutes = hours.

Kilometers 3 * 4 = 12 kilometers.

12 + 1 = 13 km.

13 divided by kilometers per hour.

A: B's speed is at least 52 km/h.

Not equal to -2 unary inequality contains a unary unknown is y

m+2)y+3 4 is a unary one-time inequality, then m is not equal to -2

Set the price at $ x.

Because of the damage of 5% of the Racha, there are only 95% of the apples.

So the cavity is dressed up (round round eggplant x

Exclude it. If you can draw a graph of the exponential function, it is simpler to first d a>1 is impossible, as the exponent increases to the n power of a will be larger than a a is also impossible, in that case, as the exponent becomes larger, the n power of a will become smaller and smaller, and then look at b.

a<-1, then if the exponent of a is negative, then the nth power of a is also negative, understand?

And a<-1, the bigger the exponent, the smaller it is, for example, a=-10, a3 is -1000, and 5 is -100000

So a 7 Then, a <-1, a absolute value must be greater than 1

Then A2 is greater than A

A 4 is greater than A 2

In 2002, the number of days of air closure was 365*55%=201 days.

In 2008, the number of days of air *** needs to be 366*55%=

So at least an increase of 256-201 = 55 days.