There is an urgent need for 20 unary inequalities, and the formula is a formula, not an application

1) 3-(a-5)>3a-4 (a<3)2) -5x+3<2x+1 (x>1 and 1/3)3)3-4[1-3(2-x)] greater than or equal to 59 (x less than or equal to -4)6 (1-1/3 1x) greater than or equal to 2+1/5 (10-15x) (x greater than or equal to -2).

5) 7x-13/6>3x-8 (x>-3)6)4x-10<15x-(8x-2) (x>-4)7) x-2-2-x>x-2/3 x-2 (x>2)8) x-2-x-6-x-4x-3 greater than or equal to 0x, less than or equal to 4).

9) x-1/3 - x-1 <1/2

10)2(5-3x)>3(4x+2)

11) 1-1/2 x >2

12）7x-2(x-3)<16

13)3(2x-1)<4(x-1)

14) 2-6 (x-5) greater than or equal to 4 (3-2x) 15) 7 + 3 x < 5 + 4x

16)5-x(x+3)>2-x(x-1)

17) x-2 (1/2 of x+2) less than or equal to 1-3 (1-x) 18) 3 (x-1) + 2 (1-3x) < 5

19) 1x-120/3) 6 (1-2x/3) <2+1/5 (10-15x) The answer is as follows.

3x+y=34

8x+3y=30

7x+4y=62

9x+2y=87

2x+5y=19

3x+5y=56

5x+2y=22

7x+7y=203

x+4y=21

5x+8y=44

3x+4y=38

4x+y=29

9x+5y=46

4x+3y=36

7x+4y=42

4x+y=41

x+6y=27

4x+7y=95

3x+6y=18

7x+9y=69

During blasting construction, the speed at which the fuse burns is 5m s, so how long does the fuse need to be in order for the ignition soldier to run to a safe area 100m away during construction?

2.If an engineering team stipulates that 300 earthworks should be completed in 6 days, and 60 earthworks are completed on the first day, and now it will be completed at least two days earlier than originally planned.

3.It is known that Li Hong is 3 years older than Wang Li, and it is known that the sum of the ages of Li Hong and Wang Li is greater than 30 and less than 33, so Li Hong's age is asked.

4.A worker plans to process 408 parts in 15 days, and adds 24 parts per day for the first three days, asking how many parts must be processed at least every day in order to exceed the task within the specified time?

5.Wang Kai's home is kilometers to the school, and now he needs to walk this section in 18 minutes. It is known that Wang Kai walks at a speed of 90 meters and runs at a speed of 210 meters.

6.An engineering team plans to repair 6km of road in 10 days, and after the construction is completed 2 days before construction, the plan changes, and the road repair task is ready to be completed 2 days in advance.

Answer: 1Set up a fuse XCM

x÷x≤16 2.After that, it will be dissipated into at least x square soil every day.

6-2)x≥300-60

x≥60 3.Let's take Li Hong's age to be x years old.

30≮x+(x-3)≮33

x 18x must be an integer x take 17

4.After setting, at least x will be processed per day.

15-3)x≥408-24×3

x≥96 5.Set x points for running and 18-x points for walking.

90(18-x)+210x≥2100

x≥4 6.After setting up x kilometers of roads per day, then.

10-2-2)x≥

6x x only see these six.

Equipped with x cars.

The total number of people is 48x

Then according to the title.

48x-（x-2）*64>32

48x-(x-2)*64<64

128-16x>32

128-16x<64

An integer when 4x is solved.

So x=5, then the cost of renting 48 bits is 5 * 250 = 125064 bit of the cost of 4 * 300 = 1200

It is clear that the comparative accounting of renting 64 bits.

There are 48 seats and X cars.

then 48x people.

64 seats. X-2 full.

64 (x-2) people.

There are also 48x-64x+128=-16x+128 people who are dissatisfied, more than half.

So 32<-16x+128<64

2<-x+8<4

6<-x<-4

4x=5 so 48 sits 5 and 64 sits 4.

Therefore, 64 seats are advantageous.

1.If the group of inequalities (x-2)(x-5)<=0, x(x-a)>=0 is the same as the inequalities (x-2)(x-5)<=0, then what is the range of values for a?

Solution of inequality (x-2)(x-5) <=0 Solution of inequality 2<=x<=5 Inequality x(x-a) >=0.

When a>0, x>a or x<0

When a=0, the inequality x 2>=0 holds constantly.

When a<0, the solution of x>0 or x=0 is.

When a>=5, the inequality group has no solution and is an empty set.

When 2<=a<5, the inequality group a=0 is the same as the inequality (x-2)(x-5)<=0, then a<2

2.Find the natural number solution of inequality group 3(x-1)+2 5x+3, (x-1) 2+x 3x-4.

The solution of a group of inequalities is x>-2

The solution of the second group of inequalities is x 7 3

So -21x>1 3

4.The system of equations 3x+2y=m+1, 4x+3y=m-1, to make x>y, find the value of m.

To write the process. 3x+2y=m+1 (1)

4x+3y=m-1 (2)

20x+15y-21x-14y=5m-5-7m-7-x+y=-2m-12

x>y, so y-x<0

2m-12<0

2m>-12

m>-6

Is it enough? Kudos me.