For math problems, you should use the hypothetical method and list the equations

Question 1: A total of 112 14 = 8 days were collected.

Assuming that all 8 days are sunny, 20 8 = 160 should be taken.

160-112 = 48 more than the actual one, the actual less picking, because the rainy day picks less, each rainy day, 20-10 = 10 less than the sunny day.

So there are rainy days 48 10 = days.

Total formula: Rainy day = (112 14 20-112) (20-10) = Question 2: 100 points for all correct answers.

100-82 = 18 points more than it actually is.

The actual score is low because there are wrong questions, and each wrong question is compared to a correct score of 5-(-1)=6 points.

So there are 18 6 = 3 questions that I got wrong.

The corresponding correct ones are 17.

Formula: Wrong = (20 5-82) [5-(-1)] = 3

112 14 = 8, assuming that 8 days are sunny then 20 8 = 160 rainy days are days.

The occurrence of decimal places is the number in the question, which may be incorrect.

Every day you take whole tens, and you can't be a whole tens.

But here's how it works: Let's say it's sunny for 8 days, and figure out the excess.

1. Set the number of sunny days x and the number of rainy days y.

Column equations have. 20x+10y=112

14(x+y)=112

The solution is x= y=

A: Rainy days are a few days.

2. Set the correct answer x and the wrong answer y.

Column equations have. x+y=20

5x-y=82

The solution is x=17 y=3

Answer: She got 17 questions right.

1. Solution: A total of 112 14 = 8 days.

Then there are x days of rain and (8-x) days of sunny days.

20×（8-x）+10x=112

x = days. A: Rainy days are a few days.

2. Solution: Set up the correct answer to the X question.

5x-（20-x）=82

x = 17 channels.

Answer: She got 17 questions right.

Question 1: Assuming that these 27 are all rabbits, then rabbits have 4x27=108 more legs than chickens, and 108-18=90 legs more than the actual ones. If you replace 1 rabbit with a chicken, the rabbit has 4 less legs and the chicken has 2 more legs, and the difference in legs will be reduced by 2+4=6.

Therefore, chickens are 90 6 = 15 and rabbits are 27-15 = 12.

Question 2: Assuming that these stamps are all 5 jiao, then the total value is yuan, which is 18-15 = 3 yuan less than the actual amount. Because we regard 1 8 jiao stamps as 5 jiao, the total value will be less, therefore, 8 jiao stamps are 3, 5 jiao stamps are 30-10 = 20 stamps.

Ding was telling the truth.

Suppose A is telling the truth, A is not a criminal. B C and D lie, then B says: D is a criminal.

is fake, then Ding is not a criminal. Ding said: I'm not a criminal or it's true.

In this way, A and D are telling the truth. So it doesn't hold.

Suppose B is telling the truth and D is a criminal. And it is true that Najia said, "I am not a criminal." So it doesn't hold.

Suppose C is telling the truth and B is a criminal. Najia and D are telling the truth. So it doesn't hold.

Suppose D is telling the truth, A, B and C are lying, and A is a criminal.

It's all yes, damn it.

Ding is telling the truth, A is a criminal.

Excluding them one by one, we can know that A, B, and C are all lying, and only D is telling the truth.

In the end, from what A said, I know that A is a criminal.

It's logical math!

It can be solved using the hypothetical method

Suppose A tells the truth and the others tell lies, then D is a criminal, which contradicts B's lies and the assumption is not valid.

Suppose B tells the truth, that D is a criminal, contradicts A who tells a lie, and that the assumption is not true that C tells the truth, then B is a criminal, and A tells a lie, that the hypothesis is not true, that Ding tells the truth, that someone else tells a lie, that A is a criminal, and B and C tell a lie The hypothesis is true.

Forehead. It's a reasoning question, and I've seen it a lot!

Suppose A tells the truth. If the other person tells a lie, then D is a criminal, and it contradicts B for telling a lie, and the assumption is not valid.

Suppose B is telling the truth. Nadine is a criminal, and he contradicts A's lies, and the assumption is not valid.

Suppose C is telling the truth. Then B is a criminal, and it contradicts A's lies, and the assumption is not valid.

Suppose Ding is telling the truth. If someone else tells a lie, then A is a criminal, and there is no contradiction between B and C telling a lie, and the assumption is valid.

1.27+4+RMB.

2.Monday: 27+4=31 yuan.

Tuesday: $31+.

Wednesday: Yuan.

Thursday: Yuan.

Friday: 32-6=26 RMB.

After comparison, it is obtained: the most ** is yuan per share this week, and the lowest price is 26 yuan per share.

A: He lost his dollars this week.

The distance traveled by the tip of the hour hand = 1 3 cm.

Assuming that none of them are broken, you can get 500 yuan.

More diverse than it actually is.

Breaking one is less than not breaking the freight yuan.

Then the one that breaks is one.

Answer: There are 3 breaks in total.

Assuming that none of the 500 is broken, the freight is yuan.

And the actual shipping cost is:

Lost shipping costs for each broken one.

So it was broken.

Mathematics + English Average Score = 98, set to A, then a = 98 * 2 = 196 Mathematics + Chinese Average Score = 93, set to B, then B = 93 * 2 = 186 Chinese + English Average Score = 91, set to C, then C = 91 * 2 = 182a + B + C = Mathematics + English + Mathematics + Chinese + Chinese + English = 2 * (Mathematics + English + Chinese) = 564

Then (Mathematics + English + Chinese) = 282

Then the average score of the three subjects is =282 3=94

Mathematics + English Grade point average = 98

Mathematics + Language Average grade = 93

Chinese + English Average grade = 91

Therefore, 2 (Mathematics + English + Chinese) = 98 + 93 + 91 = 282 The average score of the three subjects is 141

This is a primary school question, so it will be calculated according to the requirements of primary school.

98 2=196 This is the sum of the grades in Maths and English, and so on 93 2=186 91 2=182 I omitted 196+186+182=564 This is twice the sum of the results of the three subjects.564 2=282 This is the sum of the results of the three subjects.

282 3=94 That's the average of the three subjects.

Solution: Let the math be x.

In English: 98 times 2-x

The language is: 93 times 2-x

The equation is obtained: (93 times 2-x) + (98 times 2 -x) divided by 2 = 91x = 94

Okay, so that's the grade average.