An exercise in Chapter 5 of Tan Haoqiang s C Language Design 3rd Edition will help me solve it

According to my understanding, after understanding that a cone is formed by a right triangle rotated 360 degrees, it only involves some junior high school knowledge (two-point distance formula, parallel line properties), and the final v is what is sought.

#include

#include

#include

double len( double x1, double y1, double x2, double y2 );

void main()

double x = ;

double y = ;

int st = 0;

double h = ;

double c = ;

double r = ;

double v = 0;

scanf("%lf %lf", &x, &y );

if( (c = len( 2, 2, x, y ) r ) st = 1;

else if( (c = len( 2,-2, x, y ) r ) st = 1;

else if( (c = len( -2, -2, x, y ) r ) st = 1;

else if( (c = len( -2, 2, x, y ) r ) st = 1;

else v = 0;

if( st != 0 )

v = ( r-c )*h / r;

printf("v = %lf",v);

double len( double x1, double y1, double x2, double y2 )

return sqrt( (x1-x2)*(x1-x2) +y1-y2)*(y1-y2) )

What he means is that if you enter a coordinate, if this coordinate is within any of the four circles, the point is on the tower, and the tower height is 10, so the output should be 10, and any other point, the output is 0, understand?

"C++Primer" After reading it once, you will know how much gap there is between domestic C++ education and foreign ones. If you can read C++Primer thoroughly, Effective C++ and More Effective C++ will be your better choice. These three books are step-by-step, and when you understand them all, you will be considered proficient in C++.

Learn programming with ease with action**. This topic uses Tan Haoqiang's classic C++ textbook: C++ Programming (2nd Edition).