Query a one dimensional array for the existence of a specified element. Column 2 4 6 0, 1,4 Input 6,

#include

int find(int a,int s,int n,int j)int i ;

for(i=s;iif(a[i]==j)

return (i+1);

return 0;

int main()

int a[10],n=5,j,s,i;

printf("Please enter a[10]:");

for(i=0;i<10;i++)

scanf("%d",&a[i]);

printf("Please enter the number you want to find");

scanf("%d",&j);

s=find(a,0,n,j);

if(s)else

printf("There is no such number in the array");

#include

void main(),i,bflage=0,find;

printf("Please enter the number you are looking for:");

scanf("%d",&find);

for(i=0;iif(find==num[i]){

bflage=1;

printf("The subscript of the array corresponding to %d is: %d!",find,i);

if(bflage==0){

printf("Sorry, no corresponding element found! ");

printf("");

Summary. Hello dear! Glad to answer for you, C++ enters a two-dimensional array and finds all array elements less than 0 and the row and column subscripts they are in.

Here you need to use a pointer, you can use the address method (a[i]+j like this) or pointer (ptr + + like this) to input and output the elements of the two-dimensional array, and then sum the minimum value Assuming that the two-dimensional array is subscripted with 0 element is the smallest and points to the element with a pointer, the subsequent elements are compared with it, if there is a smaller one, then replace Then output its value and the corresponding pointer The address pointed by the pointer is the address of its subscript, I hope to help you!

C++ enters a two-dimensional array and finds all array elements less than 0 and the row and column subscripts in which they are located.

Hello dear! Glad to answer for you, C++ input a two-dimensional array, find out all the array elements less than 0 and the row and column subscripts where they are needed here need to use a pointer, you can use the address mountain modulo method (a[i]+j like this) or pointer (ptr++ like this) to input and output the elements of the two-dimensional array, and then sum the minimum value Assuming that the element with the subscript 0 of the two-dimensional array is the smallest and points to the element with a pointer, the subsequent elements are compared with it, and if there is a smaller teasing, it is replaced Then output its value and the corresponding pointer The address of the pointer is the address of its subscript, and Youpei hopes to help you!

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