What is the current ratio of the meter? How do I calculate the power of a meter?

300 5 is the current ratio, that is, 60 times the number on the table can be multiplied by 60 when calculating.

Since it was not possible to produce a 300A meter, it had to be scaled down by means of a transformer.

300 5 means that the current of 300A is reduced to 5A, which is reduced by 60 times. When calculating the amount of electricity, multiply the number on the meter by 60

In layman's terms: 1. The current ratio of the meter refers to the ratio of the current on the primary side (power supply side) of the transformer to the current on the secondary side (meter metering side) of the meter.

Second, the larger current directly through the meter will increase the shape of the meter, materials and costs, etc., and there are many inconveniences in installation and use, so the use of transformer (electric magnetism, magnetic generation of electricity principle) will convert the larger current into a smaller current, so that the indication, measurement and other functions.

2. The current ratio of 300 5 written on your company's electricity meter means: when the current on the power supply side is 300A (A), the current on the secondary side of the transformer is 5A (A), that is to say, when the current flows through 300A on the power supply side, the current flowing on the metering side is 5A. The value of 300 5 here should be taken as 60 (i.e., 300 divided by 5 equals 60).

3. Calculation of monthly electricity consumption:

The base number of the meter reading at the end of the month - the base number of the meter reading at the beginning of the month) x

Current ratio. Monthly electricity consumption.

kWh) Calculation of the power meter degree: (the base of the last meter reading - the base of the last meter reading) x the current ratio. Electricity consumption.

kwh) in the above equation: -

is a minus; x is the multiplier sign; =

is an equal sign; kwh

is the unit of the energy meter (kWh).

FYI.

The current ratio is 100 5, I want to calculate the actual meter degree?

Hello dear, <>

Glad to answer for you, if the current ratio is 100 5, that is, the rated current of the current meter of the meter is 5A, while the current in the actual circuit is 100A. Then, the actual meter degree can be calculated according to the following formula: actual meter degree = current meter indicator current ratio, current meter indicator refers to the reading of the current meter on the meter, the unit is a.

Or because the rated current of the current meter is 5A, if the current meter is 5A, then the actual current in the circuit is 100A. Therefore, the actual meter degree is: actual meter degree = 5 100 5 = 100 degrees.

Summary. Hello, I am glad to answer for you: "The meter measurement degree (this month's degree - the last month's degree) x current transformer ratio (such as 100 5 = 20 times) and then divide the number of wires wound in the inner hole of the transformer (if there are 2 inner holes around a circle, divide 2, and divide by 3 wires around 2 inner holes) If you pass through directly, you can omit it!

The calculated number is the actual number used! For example, directly through, 100 degrees x 20 times = 2000 degrees around a circle, 100 degrees x 20 times 2 = 1000 degrees around three times, 100 degrees x 20 times 3 degrees".

How is the actual number of meters calculated by the current ratio of 100 5.

Hello, I am inquiring for you here, please wait a while, I will reply to you immediately Hello, I am glad to answer for you: "The meter measurement degree (the degree of this month - the number of degrees of the previous month) x the current transformer ratio (such as 100 5 = 20 times) and then divide the number of wires wound in the inner hole of the transformer (such as 2 inner holes around a circle, divide 2, and divide 3 wires around the inner hole around 2 circles) If you take the punch through it directly, you can omit it! The calculated number is the actual number used!

For example: directly through, 100 degrees x 20 times = 2000 degrees around a circle, 100 degrees x 20 times 2 = 1000 degrees around the three-chain simple circle, 100 degrees x 20 times 3 degrees".

3 Hello all: should beActive powerCalculate the power consumption due to the current containedReactive current, with voltageDifferent phases, so the watt-hour meter isIt won't be meteredReactive current.

The active power isWatt (W, the power consumption isWatt-hour (wh)...1000wh =1 kWh

The machinery loaded by the motor is lighter than Hu Lao, that is, the motor power is too large. The actual power consumption of the motor varies according to the weight of the loaded machinery, not by nameplate.

Annotated power or current to calculate. The power factor should be estimated based on the actual current, actual voltage and load lightness.

and efficiency, the heavier the load of the first liter of the trousers, the higher the power factor and efficiency, and vice versa.

With the actual voltage of 410V, the actual current is 150A, which is slightly larger than the no-load operating current (about 100A), which is equivalent to 1 2 load rate

p Celery. Because the load rate corresponding to the current of 150A is about 1 2, the power factor is about, the efficiency is about and other data are estimated according to the "Electrician Common Manual" for reference, so the calculation results are the same as the watt-hour meter.

There is a slight difference in metering consumption of 48 kWh.

1》According to the power formula of symmetrical three-phase AC circuit: p

The power factor cos is generally between, take the calculation).

p The rated power of the motor should be 4kw, and the actual power is output according to the weight of the load, and the power when measured is close to the rated power.

Electricity consumption per hour is kWh; Measure the actual voltage calculation more accurately; The line voltage should be measured for three-phase loads.

2》6 second revolutions 10 1 minute revolution 60 (1 hour) 100 revolutions.

1 10 60 100 6 (degrees).

The meter measures the amount of electricity consumed: w = uit, electric power p = ui, the meter is used in the home circuit, the voltage is 220v unchanged, the current changes, the electric power changes, of course it is different.