Chicks and kittens are kept in a cage with a total of 48 heads and 120 feet, how many chicks and kit

Let's say both chicks and kittens are half :

That is, the chick has only one leg, and the kitten has only two legs;

Then the number of chicks is equal to the number of feet of the chicks;

The number of kittens is half as small as the number of kittens' feet!

So the question becomes:

Chicks and kittens are kept in a cage with a total of 48 heads and 60 feet, so the number of feet minus the number of heads is equal to the number of kittens:

60-48=12 (pcs).

The number of chicks:

48-12=36 (pcs).

It is a problem of chickens and rabbits in the same cage.

Solution 1: Suppose they are all chickens.

Feet: 2 48 = 96 (only).

Feet less 120-96 = 24 (only).

Cats: 24 (4-2) = 12 (pcs).

Chickens: 48-12 = 36 (pcs).

Solution 2: Solution: If there are x chickens, then there are (48-x) cats.

2x+4×（48-x）=120

2x+192-4x=120

192-2x=120

2x= 192-120

x= 3648-x=48-36=12

Answer: Slightly.

Let's say it's all chickens.

2*48=96 feet less.

A total of 120 feet.

12 cats. 48-12 = 36 chickens.

I don't believe that it can be checked.

Let there be x chicks and y kittens, then x+y=48, 2x+4y=120

The solution is x=36 and y=12

So 36 chicks and 12 kittens.

36 chicks and 12 kittens. Using the equation from elementary school, suppose there are x chicks and y kittens. Each chick and kitten has a head, which can be seen in Equation 1:

x+y=48 and each chick has 2 feet, and each kitten has 4 feet. Equation 2: 2x+4y=120.

Bring Equation 1: x = 48-y into Equation 2. In the end, there were 12 cats and 36 chickens.

36 chickens, 12 cats Let the number of chickens be x, the number of cats is y, x+y=48, 2x+4y=120, and then solve it.

Solution: Let there be x chickens and y kittens.

then (1) x+y=48

2)2x+4y=120

get x=36; y=12

A: There are 36 chicks and 12 kittens.

Let's say both chicks and kittens are half :

That is, the chick has only one leg, and the kitten has only two legs;

Then the number of chicks is equal to the number of feet of the chicks;

The number of kittens is less than half the number of kittens' feet!

So the question becomes:

Chicks and kittens are kept in a cage with a total of 48 heads and 60 feet, so the number of feet minus the number of hiaters is equal to the number of kittens:

60-48=12 (pcs).

The number of small Xunling chickens:

48-12=36 (pcs).

Suppose: There are chicks x and kittens y, and the system of equations is as follows: x+y=18 2x+4y=60

Shift the Qingli formula to get x=18-y and substitute it into the formula, get.

36-2y+4y=60, y=12.

18-12 = 6 pcs.

There were six chicks on the threshing floor and 12 kittens.

Hello kids, this one can have multiple answers, 1 chicken has 2 legs, 1 cat has 4 legs, so it can be launched:

1 chicken shouts liquid + 4 cats;

3 chickens, 3 cats;

5 chickens Zheng Yuan + 2 cats;

7 chickens and 1 cat.

I hope it can help you.

There may be a total of only. Such as: 1 chicken + 4 cats; 3 chickens + 3 cats; 5 chickens + 2 cats; 7 chickens + 1 cat.

Let's say 8 are all rabbits and should have feet.

8 4 32 only.

More than it actually is. 32 22 10 pcs.

Each rabbit has more feet than a chicken's feet.

4 2 2 only.

Chickens have. 10 2 5 only.

Rabbits have. 8 5 3 only.

Equation solution: Let there be x chickens and y rabbits.

x+y=92x+4y=24

The solution is x=6y=3A: There are 3 rabbits and 6 chickens.

Hypothetical solution: you can see the chicken as a golden rooster independently, and the rabbit as standing on two feet, and then divide 24 by 2=12, 12 has a total number of heads = 12-9=3 is the number of rabbits, and then use 9-3 = 6 is the number of chickens.

A: There are 3 rabbits and 6 chickens.

Solution: If there are x rabbits, then there are 9 x chickens.

4x+2*(9-x)=24

4x+2*9-2x=24

4x-2x+18=24

2x=24-18

x=6 2x=3 chickens: 9-3=6 (only).

A: 6 chickens and 3 rabbits.

Suppose the chickens have a and the rabbits have a b.

a+b=50

2a+4b=130

2x（50-b）+4b=130

100-2b+4b=130

2b=30b=15

So 15 rabbits and 35 chicks.

There are x chickens, there are y rabbits, x+y 50, 2x+4y 130, solve the system of equations, y 15, x 35, there are 35 chickens, and 15 rabbits.

At the sound of the order, he raised his two legs, and the chicks sat on the ground, and the rabbits were still standing on two legs, 130 100 30, 30 2 15, 15 rabbits, and 35 chicks.

This is similar to the classic problem of chickens and rabbits in the same cage, which can be solved with an unknown number equation. But the topic has been simplified.

1. There can be x cats. So the cat's legs are 4x pcs.

2. There are 13 chickens, and the chicken legs are 13x2 26.

3. Subtract 26 chicken legs from a total of 34 legs, and the rest is the cat's legs, so 34 26 4x

x 8 to get x 2

So the answer to this question is, there are two cats.

Calculated according to the inscription column:

2 (only) Answer: There are 2 cats.

According to the title, there are 13 chickens, so how many legs does the chicken have?

There are 34 legs in total, and minus the chicken's legs is the cat's legs.

A cat has four legs, how many cats have 8 legs?

8 4 2 pcs.

There are 2 cats.