How to do these two math problems

1.The product of the three prime numbers is 165What are these three prime numbers?

Break 165 into prime factors.

Answer: The three three numbers are .

2.Calculate in an easy way: 1 - 1 2 - 1 4 - 1 8 - 1 16 -1 32 -1 64

So the three prime numbers are 3, 5, 11

Less than half for each reduction.

So in the end it should be 1 64

1.The product of the three prime numbers is 165What are these three prime numbers?

Decompose 165 into prime factors = 3*5*11. (same upstairs) 2Calculate in an easy way: 1 - 1 2 - 1 4 - 1 8 - 1 16 -1 32 -1 64

1 - 1 2 - 1 4 - 1 8 - 1 16 -1 32 -1 64 -1 64 +1 64 [make up a 1 64].

1.Solution: Break 165 into prime factors to get 165=3*5*11

So these three prime numbers are

2.Solution: Because 1=2*1 2; 1/2+2*1*4;And so on, subtract 1 2 respectively, so that it ends up being 1 64

The prime factors are; So the three prime numbers are.

,5,The last few terms are proportional series, find the sum and subtract it.

a²-a+b=（a+c）²

a^2-a+b=a^2+c^2+2ac

2ac+a=b-c^2

2c+1)a=b-c^2

No matter what value a takes.

The equations all hold true.

So 2c+1=0

c=b-c^2=0

b=x-2y=3,xy=2

xy=2x=2/y

2/y-2y=3

2-2y^2=3y

2y 2 + 3y - 2 = 0 is factored to discuss and solve.

y+2)(2y-1)=0

y = -2 or 1 2

When y=-2, x=-1

y=1 2, x=4

2x to the fourth power y to the third power - 4x to the third power y to the fourth power.

2x) 4*y 3-(4x) 3*y 4-1152 or.

Hope it helps.

Thank you.

6. It is known that the first derivative of the function is 0 at x=a, and the second derivative is -1 3, so the maximum value is taken.

The second derivative is negative, indicating that the first derivative is decreasing at x=a, while f'(a) = 0, so the left positive and the right negative are reflected in the original function, that is, the left increases and the right decreases. Therefore, it is the maximum point) choose a3, tanx x has a limit of 1 at x = 0.

To tanx |x|, the right limit = tanx x = 1 and the left limit = tanx (-x) = -1, so it's a jump break. Select C

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