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1: Set a total of x pieces and set the specified construction period to Y days.
x/15 = y+2①
x/18 = y-3②
x15 gives x=15y+30
x18 gives x=18y-51
Get 3y=81
y=27 substitute y=27 into it.
x=435, so x=435
y=27A: There are 435 tops in this batch.
2 From the title, the number of eggs is an odd number and a multiple of 3, and this number -4 can be divided by 5, which must be greater than 30 and less than 50
That is, 393: set the total to be $x.
500+(x-500)*(1-75%)=2950=2450
x = 10300
A: The unit compensated 7,350 yuan.
All hands played!! Hope!!!
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Can you set x no?
1. Set a total of x tops x 15-2=x 18+3 to solve.
2. If there are a total of x eggs, 302 eggs, and the number of 2 eggs is left, then the number that meets the conditions is 31, 33, 35, 37, 39, 41, 43, 45, 47, 49
If the number of 3 is exactly 3, the number that meets the condition is 33, 36, 39, 42, 45, 48
5 5 numbers, then there are 4 left, and the number that meets the conditions is 34, 39, 44, 49, take the number that meets all three conditions, only 39, so there are 39 eggs in total.
3. (2950-500) (1-75%) 2950= Find.
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It took X hours to get to B with the express train.
Using the speed of the express train, the distance between A and B is 62x kilometers.
When the fast train drives to place B, the slow train runs for x-1 hour, which is 55 (x-1) kilometers, and the distance between A and B is 55 (x-1) + 195 at the speed of the slow train, so the equation is:
55(x-1)+195=62x
Solution x=20
Then the distance between A and B is 62 20 = 1240 (km) Answer: A and B are 1240 km apart.
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If the two places are separated by x kilometers, car A (i.e. express) will drive for 1 hour and then arrive at place B after y hours;
Then for car A: 62*1+62y=x;
For car B (i.e. slow car) 55y+195=x:
The solution yields x=1240 km; y = 19 hours.
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Solution: The car drove for x hours.
Then there is: 62x=195+55(x-1).
Solution x=20
Therefore, the distance between A and B is: 62*20=1240 km.
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If the express train travels a total of x hours from station A to station B, and the two stations are y kilometers apart, the equation system can be obtained: 62x=y
x-1)*55=y-195
Solving the system of equations yields x=20, y=1240
Therefore, the distance between the two stations is 1240 kilometers.
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An addition is equal to and cut another number The subtracted number is equal to the difference plus a brief description The subtraction is equal to the difference of the subtracted number 1 multiplier equals the product divided by another multiplier The dividend is equal to the quotient multiplier The divisor is equal to the quotient divided by the dividend Hope to adopt!
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Let it be that A has 7x yuan and B has 6x yuan.
7x-50)/3=(6x-50)/2
2(7x-50)=3(6x-60)
4x=80x=20
Now A = 7 * 20-50 = 90 yuan.
B = 6 * 20-60 = 60 yuan.
B = 6 * 12-
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The money on A is x and the money on B is y
x/y=7/6
x-50)/(y-60)=3/2\
The solution is x=140 y=120
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Solution: Let A be 7x and B be 6x
7x-50)/(6x-60)=3/2
x=20 A money, 7x=140 yuan.
B money: 6x=120 yuan.
Now A = 7 * 20-50 = 90 yuan.
B = 6 * 20-60 = 60 yuan.
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According to the question, set the amount of money on A's body 7x, and B's money on 6x the amount of money after buying something: A (7x-50) (6x-60)= 3 2 Solve the equation: x=20
Initially, A has money 140 and B has money 120, and the rest of the money is A 90 and B 60
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Suppose A has $7x on his body and $6 on B.
Then (7x-50) (6x-60)=3 2, solve the equation to get: x=20 so the remaining amount of money: A: 7x-50=90
B: 6x-60=60
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Solution: If the amount of money left on the armor is 3x, then the amount of money left on the body is 2x.
3x+60)∶(2x+60)=7∶6
14x+420=18x+360
x 1515 3 45 yuan .........The amount of money left on A's body.
15 2 30 yuan .........The amount of money B has left.
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Let the top bottom be x decimeters.
Divide by 2 = 60
x = 88 dm, 8 dm at the top and 12 dm at the bottom.
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(top bottom + bottom bottom) * high 2=60
Get the bottom + the bottom = 120 6 = 20 decimeters.
Top bottom: 20 (dm.)
Bottom: 20-8 = 12 dm.
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Solution: Australia raised x 10,000 sheep last year.
x-1700)/b=a
x-1700=ab
x=ab+1700
A: Australia raised AB+17 million sheep last year.
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Solution: Australia raised x 10,000 sheep last year.
axb=x-1700
x=ab+1700
A: Australia raised AB+17 million sheep last year.
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