There is a math problem, 15 in elementary school

384 kg I calculated that five eighths of 6 baskets, three-eighths of some baskets and 24 kg more, so it was calculated that the integer baskets it contained were 3, so that each basket could hold 40 kg, so there were 384 kg in total.

Set the tomatoes in the vegetable garden as x

5 8x=6 baskets.

3 8x=18 5 baskets rule.

By the time three-eighths of the whole were collected, 3 baskets were filled with 24 kilograms more.

So. 3 5 baskets = 24 kg.

1 basket = 40 kg.

So. A total of 3 * 40 + 24 + 6 * 40 = 384 kg of tomatoes were harvested.

The remaining 5 8 is loaded with 6 baskets, so one basket is loaded: 5 8 6 = 5 48 When 3 8 is received, 3 baskets and 24 kg are loaded, that is: 5 48 * 3 = 5 16 and 24 kg.

Then the ratio corresponding to 24 kg is: 3 8-5 16 = 1 16 So, there is a total of 24 [1 16] = 384 kg.

5 8 is 6 baskets, then.

3 8 should be 3 baskets plus 24 kg;

3 baskets should be so there is.

Kilogram. So together it is 24 * 16 = 384 kg.

5/8 of 384kg of all tomatoes fill 6 baskets, indicating that 3 baskets are less than 3/8 full, and 4 baskets are more than 3/8, from which the equation is obtained:

3/8)x=3*(5/8*6)x+24

x=16*24

x=384

Hehe. Pass by.

Excuse me. I'm dizzy too

Therefore, the ratio of the distance traveled by the hunting dog to the distance traveled by the rabbit is 14:11 14 (14+11)=14 25 of the circumference of the parallelogram of the rabbit 11 (14+11)=11 25 more than 6*2=12 (m).

The circumference of the parallelogram is 12 (14, 25-11, 25) = 100 (meters), and the simplest equation is: 6 1 2-11 (11+14) = 100 (meters).

A is one-third of the sum of the other three numbers, i.e., A is 1 4 of the total.

The number B is a quarter of the sum of the other three numbers, that is, B accounts for 1 5 of the total.

C is one-fifth of the sum of the other three numbers, that is, C accounts for 1 6 of the total.

10 meters = 100 decimeters.

8 meters = 80 decimeters.

2 meters = 20 decimeters.

100 80 + 20 100 2 + 20 80 2 = 15200 decimeters 15200 (2 2) = 3800 blocks.

The area of the pool is s1 = 2 * 8 * 2 + 2 * 10 * 2 + 10 * 8 = 152

Tile area s2=

First set: Let the original girl x person and then list the equation x-x 6:82-x=7:8 according to the meaning of the problem: 8*5x 6=7*(82-x).

20x/3=574-7x

41x/3=574

x=42 It turns out that there are 42 girls and 40 boys.

Set the original girl x person.

x-x/6：82-x=7：8

8*5x/6=7*(82-x)

20x/3=574-7x

41x/3=574

x=42 It turns out that there are 42 girls and 40 boys.

Set the original girl x person.

x-x/6：82-x=7：8

8*5x/6=7*(82-x)

20x/3=574-7x

41x/3=574

x=42 It turns out that there are 42 girls and 40 boys.

x-x/6：82-x=7：8

8*5x/6=7*(82-x)

20x/3=574-7x

41x/3=574

x=42 It turns out that there are 42 girls and 40 boys.

Male than female = 8:7, then the total number of men and women is (8 + 7 =) 15 multiples, then respectively with 15 30 45 60 75 80, only 75 in line with the female students walked one-sixth, that is, now 35 girls, 7 walked, the original 42, 40 boys, so it is easier to understand, the specific equation is better...

There are 40 boys and 42 girls.

Set the original girl x person.

After one-sixth of the girls are gone, male: female = 8: five-sixths x

Is it a sixth of the choir or a sixth of the girls?