Knowing that b is a positive number and b 1 b is 18, what is the value of b 1 b?

Because: a -b = a-b) (a + ab + b) 26 a-b = 2

So: a + ab + b = 13

Also: a-b) a -2ab + b = 4 - can get:

3ab = 13 - 4 = 9

So, ab = 3

Substituting the formula into the formula, you get:

a²+b² =13 -ab = 10

Solution: a-b=2, a-b =26, i.e., (a-b)(a +ab+b) = 26, so there is a +ab+b =13

a +ab+b = a -2ab + b +3ab = (a-b) +3ab = 13, then 4 + 3ab = 13, the solution is: ab = 3

then a +b = a +ab + b -ab = 13-3 = 10

a-b=±3

Solve the source of hunger: Oak suspicion due to.

a-b)²a²-2ab+b²

a²+2ab+b²-4ab

a+b) Beam split-4ab

So. a-b=±3

a+b)²=a²+b²+2ab=13

ab = 1, a + b liquid stuff = 13-2 = 11

a-b) =a Noisy bend + b -2ab=9

So volcanic a-b = 3

Perfect square formula, a +2ab+b = (a+b) =23+2=25 or so root numbers, a+b = 5, since a, b are positive real numbers, so a+b=5

<> answer: the shed is as boring as a cover and a chain of branches.

<> Tu Chi shed is full of noise and uproar.

a^3b+ab^3-2a^2b+2ab^2=7ab-8ab(a^2+b^2)-2ab(a-b)=7ab-8ab(a^2-2ab+b^2)-2ab(a-b)=-2a^2b^2+7ab-8

ab[(a-b)^2-a(a-b)+1]=-2(a^2b^2-4ab+4)

ab(a-b-1) 2=-2(ab-2) 2 Because a and b are positive numbers, only two square numbers are 0.

i.e. a-b-1=0, ab-2=0, the solution of the joint cube is as follows, a=2, b=1

a^2-b^2=2^2-1^2=4-1=3

a 3 b 3 a 2 b 2, (a b) (a 2 ab b 2) (a b) (a b) (a b), and a, b equal, a 2 ab b b 2 a b, (a b) 2 ab a b.

A and b are both positive, (a b) 2 ab (a b) 2, (a b) 2 a b, a b 1. ··

a＋b）^2－ab＝a＋b，∴（a＋b）^2－（a＋b）＝ab，∴2√［（a＋b）^2－（a＋b）］＝2√（ab）＜a＋b，∴4（a＋b）^2－4（a＋b）＜（a＋b）^2，3（a＋b）^2＜4（a＋b），∴a＋b＜4/3。·· Obtained by: 1 a b 4 3.

a+b>1 doesn't seem to be provable, I can only prove 0 a b 4 3