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Anonymous users2024-02-09The square of a + the square of b - 6a + 2b + 10 = 0
It can be reduced to the square of a - the square of 6a + 9 + b + the square of 2b + 1 = 0 (that is, 10 is split into 9 and 1).
The square of two perfect squares (a-3) + the square of (b+1) = 0 As we know, perfect squares are all greater than or equal to 0, and if the sum is 0, each term must be 0
i.e. (a-3) is squared to 0 and gives a=3 the same way.
b+1) is 0 to get b=-1
Bring in what you ask for answer 2
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Anonymous users2024-02-08Process: the square of a + the square of b-6a + 2b + 10 = 0 Simplification: (a-3) squared + b+1) squared = 0 because the square of (a-3) is a number greater than or equal to 0 and the square of (b+1) is also a number greater than or equal to 0.
and the square of (a-3) + b+1) = 0, so the square of (a-3) = 0 and the square of (b+1) = 0, so a=3 and b=-1
So the square of a-the square of b = 3*3 - 1)*(1) = 88 and the cube root is 2
That is: the square of a - the cube root of the square of b = 2
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Anonymous users2024-02-07The square of a + the square of b - 6a + 2b + 10 = 0
then (a-3) +b+1) = 0
So a=3, b=-1
So a -b = 9 - 1 = 8
So the cubic root of a -b is 2
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Anonymous users2024-02-06a2+b2-6a+2b+10=(a2-6a+9)+(b2+2b+1)=(a-3)^2+(b+1)^2=0
The bright state (a-3) 2 and (b+1) 2 are both greater than or equal to 0, to be equal to 0, only the cavity is hidden as 0 when the same respect circle source, so a=3, b=-1
The square of a - the value of the square of b = 2
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Anonymous users2024-02-05(a+b) squared = 10, (a-b) squared = 5a 2 + 2ab + b 2 = 10 ,......1）
a^2-2ab+b^2=5……（2）
So 4ab=5, ab=5 4
Obtained from (1) + (2).
2（a^2+b^2）=15
So a 2 + b 2 = 15 2 =
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Anonymous users2024-02-04a²-6a＋b²+10b+34=0
a -6a+9)+(b trousers +10b+25)=0a-3) +6+5) =0
a=b²-a²
16=4,1,A 2-6A+B 2+10B+34=A 2-6A+9+B 2+10B+25=(A-3) 2+(B+5) 2=0 So A=3,B=-5
b 2-a 2), 2, known state liquid a, b satisfies the square of a-6a+b's square+10b+34=0, find the square of b - the square of a's arithmetic square book pure root.
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Anonymous users2024-02-03(a+b) squared = 25
That is, a square + b square + 2ab = 25
a-b) squared = 9
That is, a square + b square - 2ab = 9
The sum of the two formulas.
2 (a square + b squared) = 34
The square of a + the square of b = 17
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Anonymous users2024-02-02Hello, I have seen your question and am sorting out the answer, please wait a while
5。Rationale: a+2b=25=5.
5。Rationale: a+2b=25=5. Hope mine helps you! If you are satisfied, ask for a five-star review!
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Anonymous users2024-02-01The square of a is 2a + the square of b + 6b + 10 = 0
a²-2a+1+b²+6b+9=0
a-1)²+b+3)²=0
a-1=0,b+3=0
a=1,b=-3
Square root of a-b = square root of 4 = 2
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Anonymous users2024-01-31a²-2a+1+b²-10b+25=0
a-1)²+b-5)²=0
a-1=0b-5=0
a=1b=5
b a=5 is 5 or Wang Buchun - 5
Hello! This question is a question to investigate the basic properties of inequalities, and the answer is as follows, 1 n 2+1 m 2=(1 n) 2+(1 m) 2>=2*(1 n)*(1 m), so 1 mn<=((1 n) 2+(1 m) 2) 2=(a 2+b 2) (2*a 2*b 2), multiply 1 2mn by 1 2 on the left and right, and get 1 2mn<=(a 2+b 2) (4*a 2*b 2), so the maximum value of 1 2mn is (a 2+b 2) (4*a 2*b 2), I wish you good progress!
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