VB Homework Question Help 10, VB Homework Question Help

It seems that the upstairs program is also a bit wrong.

randomize

dim a(3), max, i, j, tfor i = 1 to 3

a(i) = int(rnd * 200) +1next i

max = a(1)

for i = 1 to 3

for j = i + 1 to 3

if a(j) >= a(i) then

max = a(j)

elset = a(i)

a(i) = a(j)

a(j) = t

end if

next j, i

print a(1), a(2), a(3)

i loops three times with values of 1, 2, 3

j cycles 1+2+3=6 times in i three cycles, and their values are 1; 1,2;1,2,3

k has a total of 3+3+2+3+2+2+1=14 cycles in 6 cycles of j.

Its internal n=n+1 is executed 14 times, so the value of n in the end is 14

n is initially 0

Entering the first loop, i is calculated from 1-3.

In the second loop, the value of j is calculated from 1 to the value of i at that time.

In the third loop, the value of k is equal to the value of j at that time and the value is 3.

Finally, the calculation of n plus 1 is performed.

The final value of n is 3+3+2+3+2+1=14

i=1, j loops from 1-1, k=j=1, then k loops from 1 to 3, n is operated 3 times in this loop, and the value after coming out is n=3

i=2, j loops from 1-2, k=j=1, then k loops from 1 to 3, n is operated 3 times in this loop, and the value after coming out is n=6

i=2, j loops from 1-2, k=j=2, then k loops from 2 to 3, n is operated 2 times in this loop, and the value after coming out is n=8

i=3, j loops from 1-3, k=j=1, then k loops from 1 to 3, n is operated 3 times in this loop, and the value after coming out is n=11

i=3, j cycles from 1-3, k=j=2, then k cycles from 2 to 3, n is operated 2 times in this cycle, and the value after coming out is n=13

i=3, j cycles from 1-3, k=j=3, then k cycles from 3 to 3, n is operated 1 time in this cycle, and the value after coming out is n=14