VB basic homework, help. A vb question, begging for help

i=1,j=1:x(1,1)=x(0,0)+1+1=2i=1,j=2:x(1,2)=x(0,1)+1+2=3...

i=1,j=5:(x,5)=x(0,4)+1+6=6---

i=2,j=1:x(2,1)=x(1,0)+2+1=3i=2,j=2:x(2,2)=x(1,1)+2+2=2+2+2=6i=2,j=3:

x(2,3)=x(1,2)+2+3=3+2+3=8 and so on, the result can be obtained.

And so it goes.

x(3,4)=x(2,3)+3+4

x(1,2)+2+3)+3+4

(x(0,1)+1+2)+2+3)+3+4=0+1+2+2+3+3+4=15

This question should be based on x(i,j)=x(i-1,j-1)+i+j recursively: the fastest x(3,4)=x(2,3)+3+4 ,x(2,3)=x(1,2)+2+3 ,x(1,2)=x(0,1)+1+2 ,x(0,1) is not assigned, so it is 0

So x(1,2)=3, then x(2,3)=8 and x(3,4)=15

i Perform 1 time.

j is executed 1 time, x(1,1)=x(0,0)+1+1=2'x(0,0) is 0 bar j executed 2 times.

x(1,2)=x(0,1)+1+2=3

j 3 times.

x(1,3)=x(0,2)+1+3=4

j 4 times.

x(1,4)=x(0,3)+1+4=5

j 5 times.

x(1,5)=x(0,4)+1+5=6

i Perform the second time.

j 1 time.

x(2,1)=x(1,0)+2+1=3

j 2 times.

x(2,2)=x(1,1)+2+2=2+2+2=6j 3 times.

x(2,3)=x(1,2)+2+3=3+2+3=8j 4 times.

x(2,4)=x(1,3)+2+4=4+2+4=10j 5 times.

x(2,5)=x(1,4)+2+5=5+2+5=12i.

j 1 time.

x(3,1)=x(2,0)+3+1=4

j 2 times.

x(3,2)=x(2,1)+3+2=3+2+3=8j.

x(3,3)=x(2,2)+3+3=6+3+3=12j 4 times.

x(3,4)=x(2,3)+3+4=8+3+4=15 This is the answer, right, execute it 5 times.

x(3,5)=x(2,4)+3+5=10+3+5=18

The result of the run is that the reasoning is as follows:

The step size of the for loop is 10, so the variation of the loop variable i is

The value of s is 9+19+29+39=96

The last value of i is 49, not greater than 50, so do s = s - i 2 = 96-49 2=

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