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Anonymous users2024-02-111) liters (density in grams) can find the mass of CO2 Yes The question says that it is exactly a complete reaction, then what should be generated is Na2CO3 without gas being released The mass of the solution is.
2) The mass of Na2CO3 formed after the reaction is x according to the reaction equation.
CO2 + 2NaOH = Na2CO3 + H2O.
x x = mass score is.
3) After the reaction, the solution is Na2CO3 solution, Na2CO3 is easy to hydrolyze to form OH- ions, so the solution is alkaline, and the pH should be greater than 7 at room temperature
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Anonymous users2024-02-101) grams.
3) Because sodium carbonate is generated, the solution is alkaline and the pH value is greater than 7.
Don't blame me for being wrong.
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Anonymous users2024-02-09A 300ml solution is 300*
354g*, that is, the amount of magnesium ion is 24g mol, so the only amount of chloride ion is .
So the amount concentration is.
So it's D and the second question is C
The number of electrons contained in sodium metal (1 sodium metal should contain 11 electrons, so it is 11mol).
b.The number of molecules contained in benzene under standard conditions (benzene is solid under standard conditions.
So benzene will not be 1mol).
The number of atoms contained (this is the definition.)
Definition of Avogadro's constant).
The number of H ions contained in the sulfuric acid solution (the amount of hydrogen ion substances should be 2mol of sulfate is containing two hydrogen ions).
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Anonymous users2024-02-08Nitrate is heated to see how active oxygen ions are determined.
1) Na, K et al. generate nitrite and oxygen (2) NH4, generate N2, H2O This**(3) common excessive metals produce corresponding oxides, O2 and water.
4) Heavy transition metals, forming elemental metals, oxygen and water...
The front one is potassium nitrite and the back thing is barium oxide.
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Anonymous users2024-02-07There are three cases for the thermal decomposition of nitrate:
1. Nitrate decomposition of alkali metals and alkaline earth metals produces nitrite and O2, such as: 2kNO3=2kno2 O2
2. The decomposition products of metals with electrochemical order between Mg-Cu are M oxide, NO2 and O2 due to nitrite instability, such as: 2Cu(NO3)2=2CuO+4NO2 +O2
3. M after the potential order Cu, because of its unstable M oxide, decomposes to produce M element, such as: 2AGnO3=2AG2NO2+O2
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1. Greater than 2Because CH3COOH is a weak electrolyte, only part of CH3COOH is ionized in the solution, and C(H+) in the solution has a pH greater than 2 >>>More