Push a wooden box placed on the level ground with a force of 5n, and the wooden box is stationary a

Don't you explain it in more detail? The landlord is not for the answers.

First of all, we use 5N to push the box, and then it doesn't move, which means that the static friction is 5N at this time, and the same is true with 8N, but the static friction can be greater than or equal to the sliding friction.

Positive solution - the wooden box is stationary, the state of motion is unchanged (constant), and it must be subjected to (static) friction in the opposite direction of the thrust, so the thrust and static friction are equal in magnitude (same). The landlord gave a big point.

Push a wooden box placed on the horizontal ground with a force of 5n, the wooden box is stationary, the static friction of the wooden box is changed to 8n to push, the wooden box is still stationary, and the static friction of the wooden box is 8n at this time

Reason: The wooden box is stationary, the state of motion is unchanged, and it must be affected by the equilibrium force, so the thrust and static friction force are equal in magnitude.

5n, 8n, rest, static friction in the opposite direction of the magnitude of the thrust, equal.

, no change, the equilibrium force acts, equal.

5n 8n

Remain the same. Equilibrant. Equal.

5n, 8n, unchanged, static friction in the opposite direction of the magnitude of the thrust, equal.

5 Newtons 8 twists to one Constant Reaction force equal.

Push a wooden box placed on the horizontal ground with a force of 5n, the wooden box is stationary, the static friction of the wooden box is changed to 8n to push, the wooden box is still stationary, and the static friction of the wooden box is 8n at this time

Reason: The wooden box is stationary, the state of motion is unchanged, and it must be affected by the balance force, so the thrust and static friction are large.

The size is equal

5n, 8n, in equilibrium, the force in the opposite direction, the equivalent is reversed.

5n 8n

The resting static friction is equal.

5n "From Newton's first law, the net external force on a body at rest is 0"; 8n Same as above.

If the ground is level, there is no friction, and if the ground is tilted, there is friction.

This has to be explained according to the force on the object: when the object is subjected to a balanced force, it always maintains a state of constant motion or a state of rest. Conversely, when an object remains in a state of constant motion or at rest, it is subject to a constant equilibrium force.

Because when the object is subjected to a tensile force of 5N, the wooden box does not move, that is, it remains at rest, so the object is subjected to the action of the equilibrium force at this time. Hope you understand!

Because the wooden box is subjected to the action of static friction, the static friction is equal to the tensile force.

Specific analysis: the wooden box is in a state of equilibrium, the force is balanced, and it is subjected to the right tension, and it must also be subjected to the equivalent reverse force, that is, the static friction force. Hope.

You have as much friction as you use, and it doesn't change when you get past the maximum friction.

2.The wooden box is not right under the tensile force of 8N, so the friction force experienced by the box is static friction, and the size is 8N.

3.When the wooden box is under the action of 12n horizontal tension, the box accelerates, so it is subjected to sliding friction, and the magnitude is.

Hello, it is a pleasure to answer your questions, I hope my answers will be helpful to you. 1. The sliding friction is positive pressure, so the friction factor is the static friction force at this time, and the size is as long as the object is sliding, no matter how much the tensile force is.

If the wooden box is in a state of stationary or uniform linear motion, that is, when it is in a state of equilibrium! The horizontal direction of the two forces is balanced, and the friction force is equal to the thrust magnitude! i.e. 100n!

If it weren't for the above, it would be a different story! Your question is not very specific! By the way, are you a junior high school student or a high school student? My gut feeling is that you're a junior high school student!

If the wooden box cannot be pushed, the friction force is 100 N, otherwise it is f = kmg (k is the friction coefficient m is the mass of the wooden box g = can be about 10).

There is something wrong with this question! Know that you're not giving positive pressure!

Sliding friction f=

When the wooden box is pushed with a horizontal force of 70N, the thrust force is less than the sliding friction force, and the wooden box cannot be pushed, and the wooden box is stationary, so the friction force on the wooden box is 70N

When the wooden box is pushed with a horizontal force of 150N, the thrust is greater than the sliding friction, which can push the wooden box to be hand-held, and the wooden box is cracked before accelerating, so the friction of the wooden box is 100N (the sliding friction has nothing to do with the speed of Bimin, so it remains unchanged).

I don't know what to ask about.

According to the formula of friction force of the sliding cover, 400N multiplied is equal to 100N, Zhiyin Stuffy Kai did not push with 70N, according to the balance of the two forces at the level of the front, so the friction is 70N, if it is pushed with 150N, pushed, the sliding friction is 100N.

400* So if the world uses 70n to push and the box does not move, the only friction is 70n, which is static friction, and 150n pushes, and the friction is 100n

If it is stationary without pulling, or if it moves in a straight line at a uniform speed, then the frictional force is 5N, because both the stationary and the linear motion at uniform speed are in equilibrium, and the tensile force and the frictional force are equal. If it is an accelerated motion, the pulling force is greater than the frictional force.

Please click here, you can ask if you don't know.

If pulled, friction has nothing to do with tension, only with gravity and friction coefficient; If it is not pulled, it means that the coefficient of friction multiplied by gravity is greater than or equal to the pulling force, and the friction force at this time is equal to the pulling force.

If it is not pulled, stationary, or moving at a constant speed, it is friction = tension = 5n

If the box is not moving or moving at a constant speed is 5N, then the two are equal. If it weren't for the above, it wouldn't be equal.

Not necessarily, unless there is no pull or a constant motion.

I know what your problem is.

Static friction has a maximum critical point, such as 10 Newtons, if you push the box without pushing, then the combined external force of the box is 0, that is to say, your thrust must be less than 10 Newtons, at this time how strong you are, how much friction the box has, for example, if you use 6 Newtons, then the friction force is 6 Newtons.

Unless your thrust is greater than 10 N, and the box is pushed, then your thrust is greater than the friction, and before that, as long as the box is not moving, it is a two-force balance, then the friction is equal to the thrust.

Thank you and I'm very happy if it can help you!

Chairman of Gobi Frog!

According to Newton's laws of motion: when an object is subjected to a balanced force, it always remains at rest or in a state of uniform motion. Conversely, if the object remains at rest or in a straight line at a uniform velocity, then the object must be subject to a balancing force.

Because when a force is used to push a wooden box, there is no push, indicating that the object is at rest. Then it must be acted upon by the equilibrium force, i.e. the thrust force is equal to the frictional force: f=f.

Because the wooden box is in a state of force equilibrium, it is equal to.

The relationship between thrust and friction is equal to.