A 400KW power transformer uses 60 loads, can it be connected to the capacitor cabinet to reduce the

Of course!

If your electrical equipment is not compensated on the spot, you must have a capacitor cabinet as a centralized compensation, if there is no both, the system power factor will be too low, and the line consumption will increase, on the other hand, the power factor is lower because of too much reactive power drawn from the grid), the power supply company will also be fined.

The friend upstairs confused the concepts of transformer efficiency and power factor.

Transformer efficiency refers to the ratio of transformer output power to input power, which describes the transfer of transformer energy; The power factor refers to the ratio of active power to apparent power, and it describes the degree to which the current lags behind the voltage in the system, which are two completely different concepts. According to the formula: p=, the lower the power factor, the greater the current required to transmit the same power, and the greater the loss on the line.

The national electricity standard stipulates that the power factor of the low-voltage system of industrial production cannot be lower, if you find that there is an item of "power adjustment fee" in the electricity bill, it means that your power factor is too low and you are fined. In addition, if the power factor is too low, the loss on the line in the plant cannot be ignored.

If you have a lot of inductive load per unit, it is recommended to add reactive power compensation equipment, which is more cost-effective from the perspective of long-term operation.

If you connect the capacitor to the transformer, that's not necessary! The transformer is a high-efficiency energy transmission equipment, and the reactive power will be large only when there is no load, but the total power loss at no load is still very small! The larger the transformer capacity, the smaller the no-load power loss!

Your transformer is in normal operation, the output power and the input power are very close, what compensation is needed? The so-called compensation is generally designed for the inductive load of the low-voltage user! The requirements for urban office buildings are above, the requirements for factories are above, and the requirements for agricultural indoctrination production are above!

The power company's requirement is local compensation, and the capacitor at the input end of the transformer is also for the above, such compensation is generally used in high-voltage power distribution stations! It is used to compensate for the loss of energy in high-voltage transmission!

I think the specific situation depends on your power factor level, if the power factor is not high, it can be connected.

If it's high enough, there's no need to connect it, after all, the capacitor cabinet isn't cheap.

A 1600kva transformer, the total power of our equipment is 1000kw, the monthly electricity is 180000 kWh, and the load ratio is what is the calendar key.

Hello dear, the load ratio is 1000kw 1600kva 100% =. The load ratio refers to the ratio between the actual electrical load and the rated capacity of the transformer, which is expressed as a percentage. In this problem, the total power of the equipment is 1000kw, and the capacity of the transformer is 1600kva, so the load is 1000kw 1600kva 100% =

This means that the total envy power of the equipment accounts for the rated capacity of the transformer.

It operates continuously within the range of the rated current and the oil temperature of the upper layer of the transformer does not exceed 85 degrees. The power factor is between 85-95% and the economic benefits are the best.

The operating efficiency of a single transformer is the highest point, and the condition is: when the variable loss (coil copper loss) is equal to the constant loss (core loss), the general load factor is about 60% of the rated load, which is the highest point of efficiency.

As for how much load to carry, it is necessary to consider the situation of the same period, and the general situation is that the apparent power does not exceed the total capacity of the transformer during the peak load period.

Capacitance compensation should consider the load nature and the power factor before uncompensation, and provide an example reference:

Q: Increasing the power factor from to the required compensation capacity compared to increasing the power factor from the required compensation capacity (a.)As much as bMore cLess dNot necessarily.

Choose; b！Explanation: According to the calculation formula of reactive power compensation

qc=p(tg a1－tg a2)

Where: qc is the capacitance value of the capacitor that needs to be compensated, unit: kvar

p is the active power of the system, which can be regarded as a definite active power value in kW

tg a1, which is the tangent of the phase angle of the power factor cos a1 before compensation.

tg a2 is the tangent of the phase angle of the power factor cos a2 after compensation.

For the increase to, the trigonometric formula is used to calculate: tg a1=, tg a2=

Bring in the previous formula:

qc＝p*（ kvar)

For the increase to, the trigonometric formula is used to calculate: tg a1=, tg a2=

Bring in the previous formula:

qc＝p*（ kvar)

This shows that when the power factor is low, the cost of increasing the power factor is easier than when the original power factor is high. Exams with students are a truth. Students who usually score points will have to score 80 or 90 points, which is easier than students who usually score 90 points and want to score 99 points.

For the convenience of daily work, (tg a1 tg a2) in the above calculation is usually called: the amount of compensation required from a1 to a2 per kilowatt of active work. And compiled into ** for future reference, in order to reduce triangulation calculations.

What is the no-load loss of a 35kV to 10kV three-phase transformer with a capacity of 20,000 (20,000) kva and the loss of a 10,000kw load?

Dear, hello, the capacity of 20000kva, the no-load loss of the 35kV to 10kV three-phase transformer is 40kw, and the fuel consumption of the loss is PH*IH1=10*. Carry width.