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Anonymous users2024-02-11The principle of lever is like prying something, and the arm is long. The same distance is less effortless, but it takes longer. The scientific point is that the force of a rope is the same, the original 100kg weight is borne by a rope, but if the rope is folded in half, then the force of each rope is only 50kg, the force diagram is very easy, two wires, two forces, one line, one force and that's it.
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Anonymous users2024-02-10First of all, only the moving pulley will save effort, and secondly, the tension on a rope is equal everywhere, so the force on the whole rope after a rope bypasses a moving pulley is still unchanged, and then the force on the rope on the left side of the pulley plus the force on the right rope is not the original 2 times...
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Anonymous users2024-02-09The position of the axis is pulled along with the [url]http: object[url]http:[url]http:[url]http:[url]http:[url]http:[url]http:[url
The pulley [url] is called a movable pulley. The movable pulley is essentially a lever in which the power arm is equal to 2 times the resistance arm. (Only for the time when there are only two ropes next to the movable pulley, f1=f2 n, n is the number of rope segments next to the movable pulley) Formula:
f1·l1=f2·l2 got it.
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Anonymous users2024-02-08Each section of the rope that shares the force is evenly stressed.
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Anonymous users2024-02-07The force is the same at each point on the rope.
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Anonymous users2024-02-06Think of it as leverage.
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Anonymous users2024-02-05Using the Pythagorean theorem, the first x = root number five, which is approximately equal to, between 2 and 3.
The second is the other way around, x = 3 root number 5, which is approximately equal to, between six and seven.
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Anonymous users2024-02-04Pythagorean theorem, a square + b square = c square (c is the hypotenuse.
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Anonymous users2024-02-03What is 2013 to the 2014 power minus 2014 to the 2013 power.
Your Qingqin's problem should be to compare the size of 2013 2014 and 2014 2013. You can't make a difference, you should compare it.
Lutong 2013 (1, 2) 2013
i.e. (2013, 2014, 2014) (2014, 2013) 1, so 2013, 2014, 2014, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013, 2013
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Anonymous users2024-02-02Point P on the angular bisector oc of AOB , PE ob, PD=PE, DOP= Fengtong EOP, PDO= PE=90°, DPO EPO, DPO= EPO, DPF= EPF, in DPF and EPF, PD=PE, DPF= EPF, and PKI attack PF=PF
dpf≌△epf
df=ef．
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