Please talk about this chemistry, please talk about this chemistry problem

Strong acids and alkalis will inhibit the ionization of water, and weak acids can promote the ionization of water. Among the weak acids, acetic acid is more acidic than ammonium ions, so 4>2. A strong alkali will inhibit the ionization of hydroxide ions from water more, and a strong acid will inhibit the concentration of hydrogen ions ionized by water, so 3>1.

So the answer is 4>2>3>1.

The chemical formula of ammonium sulfate is (NH4)2SO4, so the ammonium concentration is molar, and the concentration of 6 is the maximum. Ammonium bisulfate and ammonium chloride are both acidic solutions, but ammonium bisulfate is more acidic, because it has hydrogen ions, and hydrogen ions will inhibit ammonium hydrolysis, so 7>4. Ammonium acetate is generally considered to be a neutral solution, with weak acid and weak base hydrolyzed at the same time, in which the concentration of ammonium ions is lower than that of ammonia solution with strong base ions, that is, 4>5.

The main ingredient in ammonia is a weak alkaline solution, in which there is only a small amount of ammonium ions, so 5>8

Final: 6>7> 4>5>8

Ammonium in ammonium chloride example and oh- bind, promote the ionization of water, which has the most H+ and ranks first.

The other 3 are all inhibiting water ionization, and acetic acid is a weak acid with weak inhibition ability, ranking second.

A sulfate has 2 hydrogen ions, which has the strongest inhibition ability and ranks last.

The second null is mainly , 7 to 4 pairs because the hydrogen ions decomposed in ammonium bisulfate inhibit the binding of ammonium and water, while ammonium chloride has some ammonia and water combined. It's too troublesome to type and explain one by one, and the rest should be fine, and you can ask me if you don't understand.

I didn't read the question clearly, but upstairs is the correct solution.

Junior high school questions, ask the junior high school teacher to go.

1.The molecular formula is the number of c, h, and o atoms in the number. Note that there is carbon at the endpoints and inflection points in the bond type, and the number of bonds plus hydrogen is equal to four.

2. Hydrolysis under acidic conditions is two ester bonds. After hydrolysis, it is three molecules, and the same on both sides is acetic acid 3The fair side of the molecule is the two benzene rings and the connected carbon atom 4

The carbon-oxygen double bond on the ester bond cannot be added, so here only the benzene ring can be added. So it's 5mol. The two benzene rings are combined together, and the common parts can no longer be added.

5.It reacts with sodium hydroxide as a hydrolysis reaction. Sodium acetate and phenol are formed by hydrolysis under alkaline conditions, and phenol reacts with sodium hydroxide. So it's 4mol. The hydrolysis of the halogen atoms on the phenol ester and the benzene ring consumes 2 sodium hydroxide.

Quite simply, the benzene molecule is a planar structure, and the naphthalene molecule and the carbon on the methyl group have a total of 11 coplanarities;

The ester groups on both sides of K4 have a symmetrical structure, and there are two kinds of hydrolysates.

Only the double bond on the benzene ring can be added, that is, it can be added with 5mol of hydrogen;

After the ester group is hydrolyzed, the hydroxyl group on the benzene ring can also react with NaOH as phenol, so 2+2 gets 4.

The first one is not to be said, the question of counting; Compounds contain ester groups, which are hydrolyzed by acid to form acetic acid and compounds containing phenolic hydroxyl groups; The benzene ring and the atoms directly connected to it are coplanar, count; With hydrogen addition, do not consider the double bond in the ester group; In the reaction with sodium hydroxide, in addition to considering the hydrolysis of ester groups, why should the phenolic hydroxyl group in the product be considered to react with sodium hydroxide! Hope for good reviews, I'm tired to death!

1.The molecular formula is to look up the number of atoms;

2.The hydrolysate is phenol and two acetic acids;

3.two benzene rings of coplanar carbon atoms and 11 methyl carbons on them;

4.There is a 5mol double bond, 5molH2 is required;

Hydrolysis under the action, the product has two phenolic hydroxyl groups and two carboxyl groups, and 4 NaOH are required.

The handwriting is pretty beautiful, hehe.

Let's talk about this topic, the first step of this equation is to write the reactant ions at both ends of the reaction, and the conservation of electrons and the valence of each element according to the gain and loss of the redox reaction;

The second part: combined with the acidity and alkalinity of the reaction environment, the conservation of charge is used, and H+ (acidic) or OH- (alkaline) is added, which is the same number of charges at both ends of the reaction formula, and the addition position is mainly determined by the number of charges on both sides.

Part 3: According to the O in the reaction formula, the number of h is conserved, and if you don't understand the chemical problems of supplementing H2O, you can add QQ to ask me, hehe.

It is mainly judged by the substance that precedes the reflection.

Because the reaction substances are manganese dioxide, as well as sulfuric acid.

Then naturally hydrogen ions will be written in front.

That's generally the case.

For example, acidic potassium permanganate, that is, hydrogen ions before the reaction do not know how to ask.

The reaction should take place in an acidic solution, because manganese dioxide is insoluble in water, first dissolved in acid to form tetravalent manganese, and then iron redox reaction with divalent iron, so the front should be hydrogenated, and the back should be water.

Hydrogen ions are written in the front, there are sulfate ions, and if hydrogen ions are written in the back, then, what are the anions?

A, all are monosaccharides, the chemical formula is the same (C6H12O6). B, the chemical formula is (C3H6O2). c, all butane (C4H10). d, starch and cellulose are both mixtures. So choose D.

Starch and cellulose are mixtures, and only the similar molecular structures of pure substances can be said to be isomers, and mixtures are not isomers at all.

The molecular formula of starch and cellulose is (C6H12O)N

Because of the uncertainty of n, they are not called isomers of each other.

And because of the uncertainty of n, they themselves are also mixtures.

This is a little unclear. Can you be a little clearer.

According to the first coordinate, it can be seen that the concentration of the substance of a changes from, indicating that the concentration of the substance reacted by a c(a)=

The amount concentration of the substance of b changes from to the amount of concentration of the substance reacted by b.

The amount of the substance C(B)=C changes from 0mol l, indicating that C is the product, and the concentration of the substance that produces C.

c(c) = then the ratio of the measured numbers of the three substances =: 3:2

The chemical equation of the reaction: a+3b = 2c

a The positive reaction of this reaction is that the volume of the gas decreases, so the pressure is increased, and the equilibrium moves to the direction of the positive reaction, so a is wrong;

According to the second coordinate system, the temperature t1>t2 can be known, and the volume fraction of the increased temperature b increases, indicating that the flat ant moves in the opposite direction, and the positive reaction is an exothermic reaction, so the conversion rate of a decreases, and b is wrong;

c. Keep the temperature and pressure unchanged, introduce rare gases, the volume of the container needs to be expanded, and the equilibrium moves in the direction of gas volume expansion, that is, in the direction of reverse reaction, c is wrong;

After D converts C to AB according to the half-side inversion method, the amount concentration of the buried substance of A =

The concentration of the substance of b = is equivalent to the material of the first time, that is, the equilibrium is equilibrium, so after the equilibrium is reached, the concentration of c is also correct.

Hope mine helps!

I have a different opinion, at the end of D, looking down is to see the top of the liquid level, which will make the volume difference between the front and back smaller, that is, the volume of the liquid to be measured is small, so the concentration is high.

C oxidizes from 0 valence to 2 valence, and because of the formation of 5molco, paimin, the electrophora family is transferred to 2*5=10na

Only CO is a gas, MCO=28, and the N2 amount of excess dust is also 28

a.According to the acidic nature of the solution, the ionization is greater than the hydrolysis, and the pH is only 4, so the ionization is only a small part. So correct.

b。In the mixed solution, the concentration of element f is 2 times that of sodium so wrong.

c。The solution is alkaline, so it can be considered that HCN is not ionized, only NaCN is hydrolyzed, and hydrolysis will produce HCN, so the concentration of HCN is higher than that of NA. So wrong.

d。Ammonium carbonate, because it is double hydrolyzed, promotes each other, and the degree of hydrolysis is the largest. Ammonium sulfate, only ammonium root hydrolysis, ammonium ferrous sulfate, ammonium and ferrous ions are hydrolyzed and compete with each other, so the degree of hydrolysis is minimal.

The greater the degree of hydrolysis, the lower the concentration of NH4. If the concentration of NH4 is the same, then the salt with the greatest degree of hydrolysis needs to have a higher concentration to leave enough NH4 after hydrolysis. So it's also wrong. It's the other way around.