int x 2 A x 1 x B x ,2 x C 2 x,x 2

It's OK to understand both concepts

Comma expressions are counted from left to right and the value of the comma expression is equal to the value of the rightmost expression.

The value of the assignment expression is equal to the lvalue of the assignment expression, which is the value of the number to the left of the equal sign after the assignment is complete.

So the value of a x*=(1+x) is the lvalue of the assignment, which is the value of x, which is 6

b x++, 2*x first x++ then x=3 then 2*x = 6, the value of the whole expression is equal to the value of the rightmost expression, that is, 2*x = 6

c 2*x,x+=2 Calculate 2*x = 4 first, but note that there is no assignment at this time, so the value of x is still 2, and then x+=2, and the value of the whole expression is equal to the value of the rightmost expression, which is x+=2, which is 4

Therefore the answer is cI hope mine will be helpful to you, if it is useful.

a x*=x+1 is x = x*(x+1) = 6, and the value of the whole expression is the left value after the assignment, which is the value of x, which is 6

b x++, 2*x first x++ then x=3 then 2*x = 6, the value of the whole expression is equal to the value of the rightmost expression, that is, 2*x = 6

c x*=(1+x) This is the same as a, which is 6

d 2*x, x+=2 Calculate 2*x = 4 first

But note that there is no assignment at this point, so the value of x is still 2, and then x+=2 is calculated to be equal to the value of the rightmost expression, which is x+=2, which is 4, answer d

b Not six, the rest are six and three

int x＝2；z＝-x+++1；then the value of x = 3.

The reason for this is that the x++ operation is that there will be a self-addition operation after the assignment is completed.

If you are looking for the value of z, then z=-2+1=-1

The value is not added at the time of assignment, and it is added again after the assignment is completed.

In your formula, x=3.

The reason for this is that the x++ operation is that there will be a self-addition operation after the assignment is completed.

If you are looking for the value of z, then z=-2+1=-1

The value is not added at the time of assignment, and it is added again after the assignment is completed.

1, you have to know that this is equivalent to z=x-1; x++;

To give you an example:

In greedy algorithms, x++-1 is an operator after compilation++ - is an operator.

z=x++;This means that the value is assigned first and then ++ z=x; x++;

z=++x;It's x++; z=x;

z=x-2;The value of x doesn't change, this -2 is -2 inside z, and then you can think of it as z=x; z=z-2;

So you can understand it.

z=x++-1 first assign x to z z and then from -1 then x++ so you should understand!

Summary. Dear, I'm glad to answer for you, let a, b, x are int variables, and a=5, b=6, x=2, then the expression x=a>b is calculated, the value of x is: in the expression x=a>b, first compare the size of a and b, and find that a is less than b, so the result of a>b is false.

False is then assigned to x, so x has a value of false. It's important to note that true and false in python are actually boolean variables, not integer variables. But when doing numerical operations, true is treated as 1 and false as 0, so in this problem, the value of x can be thought of as an integer variable 0.

After calculation, the value of x is.

After calculation, the value of x is.

Let a, b, and x all be int variables, and a=5, b=6, and x=2, then the expression x=a>b is operated.

int i,j;for(i=0,j=10; i<=j+1; i+=2) printf("%d",i);

In the following paragraph, the number of executions of the for loop body is.

Let a, b, and x all be int variables, and a=5, b=6, and x=2, then the expression x=a>b is operated.

After calculation, the value of x is.

Let a, b, and x all be int variables, and a=5, b=6, and x=2, then the expression x=a>b is operated.

After calculation, the value of x is.

Let a, b, and x all be int variables, and a=5, b=6, and x=2, then the expression x=a>b is operated.

After calculation, the value of x is.

Let a, b, and x all be int variables, and a=5, b=6, and x=2, then the expression x=a>b is operated.

A few lines of fierce value Lu Gao substituted into the early ruler

+a, first add the value of a to 1, a=4

x=++a,x=4

Both a and x have values of 4

Please refer to it. <>

It's OK to engage in a group tomb and understand the two concepts

Comma expressions.

It is counted from left to right.

And the value of the comma expression is equal to the value of the rightmost Wang Kai expression.

The value of the assignment expression is equal to the lvalue of the assignment expression.

That is, after the assignment is completed.

The value of the number to the left of the equal sign. So. a

x*=x+1. x

x*(x+1)

The value of the entire expression is the lvalue after the assignment is complete.

This is the value of x. That's 6b

x++,2*x

Calculate x++ first, then x=3, then 2*x

The value of the entire expression is equal to the value of the rightmost expression.

That's 2*x

cx*=(1+x)

This one is the same as A. It's 6d

2*x, x+=2 is calculated as 2*x first

But be careful. There is no assignment at this point.

So the value of x is still 2

Then calculate x+=2

The value of the entire expression is equal to the value of the rightmost expression.

I don't know what it is.

x+=2 is 4

The comma operator is a sequential point, which means that before the 2*x operation, *** of the self-incrementing operator +1 has occurred, and x becomes 3