1 Junior 2 Physics Question Urgent 1 Junior 2 Physics Question, Urgent

It's actually 100 degrees Celsius.

You asked for a number.

I'll give you another question.

Change yours: a thermometer with a uniform scale, but the indication is not accurate, insert it into the ice-water mixture and the indication is 2 degrees, put it in boiling water at standard atmospheric pressure and the indication is 94 degrees, and use him to measure a glass of water with 24 degrees, what is the actual temperature?

Solution: The actual temperature represented by each cell is 100 (94-2) degrees Celsius.

24 degrees actually rises from 2 degrees Celsius to 2 degrees Celsius, 24-2 = 22 blocks.

Then the actual temperature is 22*100 (94-2) = approximately equal to) solution: the actual temperature represented by each cell is 100 (94-2) degrees Celsius.

48 degrees actually rises from 2 degrees Celsius to 48-2=46 degrees.

Then the actual temperature is 46*100 (94-2)=50 degrees Celsius.

100 degrees for sure.

This thermometer actually represents 100 (94-2) = 25 23 degrees per scale.

If this thermometer is x degrees.

then the actual temperature is equal to (x-2)*(25 23).

If the temperature is measured 48

Actual temperature (48-2) * (25 23) = 50

1) obtained from g=mg: m=g g m=160kg2) from f=ps: p=f s

Since the object is only subject to gravity and support, the pressure here is gravity, i.e., f=gp=g s p= to the fifth power of pa

1600 (to the minus 2 power) = to the 5th power of PA

Solution: m brick =

g brick = m brick g =

n=240 25=block.

Is your answer wrong, it shouldn't be 240 10, because 240 is already force, and mass needs 10

x g =25n

Your unit of mass should be kg, and the 10 you say is actually g I don't know if your mass is converted to n... If you convert it, it's even simpler, just divide by 240 and get 96

Straight is 240. But I always feel that the topic is too simple, not like the second year of junior high school, hehe. Hope you can adopt it!

I will express the mass in kg.

Reason: Calculate the gravity of each brick g=mg=

240n 25n = But the number of blocks of bricks is an integer, so 9 blocks.

A: The switch is directly connected to both ends of the battery. Therefore, as soon as the switch is closed, the battery is short-circuited, and the wire, switch or battery is burned.

B: There is nothing wrong with this series circuit itself. It's just that after connecting in series, the sum of the voltages of the two lamps = the power supply voltage. Therefore, it is possible that the bulb is not working properly.

C: The switch is connected to both ends of L2 - the switch is connected in parallel with the electrical appliance... Therefore, when the switch is closed, L2 is short-circuited and cannot emit light.

In Figure A, when the switch is closed, it will constitute a local short circuit; There is no problem with B, and the switch in Figure C cannot control L2

Assuming that the voltage is U, the ammeter U R1 is connected to AWhen connected to B, R1 R2 is connected in series with U (R1+R2), then the two readings of the ammeter are U R1 and U (R1+R2).

Because, if the reading is 50:1, then the formula can be obtained.

u/r1:u/(r1+r2)=50:1

Eliminate u, that is.

r1+r2)/r1=50

r1=44, substitution: (44+r2)=50*44 r2=50*44-44 can be obtained.

r2=2156 ohms.

Generally, the home circuit is 220V voltage, then the current value can be obtained without i=u(r1+r2)=220 2200=amperes, then the power can be obtained: wr1= i 2*r1= watts.

This kind of problem mainly considers learning about the series connection of electrical circuits.

i(a)=u/r1, i(b)=u/(r1+r2);

i(a) i(b)=50 r1+r2) r1=50 solution r2=49r1=2156

Connected to the home circuit: U=220V I=U (R1+R2)=220 2200=

Then the power consumed by r1 is p=i 2*r1=

Solution: 1. When the switch contacts a, the current = U R1; When the switch contacts B, the current = U (R1+R2).

From the inscription: (r1+r2) r1 =50:1 r1=44 ohms.

So r2=6 ohms.

2. U=220V, R1=44, R2=6, then P=220 (44+6)*44*44=

Solution: (1) When the switches S are in contact with A and B respectively, the ratio of the indication of the ammeter is 50:1 The ratio of the current of the series circuit = the ratio of the resistance of the series circuit.

r1+r2：r1=50:1

R2=49R1=49*44=2156 (2) The home circuit voltage is 220V

And when switch S is in contact with B, R1 is connected in series with R2.

i=u/r1+r2=220v/44ω+2156ω=∴p（r1）=i²r1=（

The circuit knowledge is what we learned last semester, the teacher taught it very well, and we learned it well, I hope my answer will help you!

IR1+IR2=IR3 In series, i is equalBecause i is inversely proportional to r, r1 r3=1 50, i.e., r3=44x50= r2=

Let : voltage is u u r1:u (r1+r2)=50:1 known r1 to find r2 resistance.

Home circuit, the voltage is 220V, the current is I=U (R1+R2) when the switch is connected to B, and the power W=I 2*R1