Senior One Chemistry Help, Chemistry, Thanks, Senior One Chemistry Please help, thank you

1.By the reaction formula 2 hydrogen + 1 oxygen = 1 water.

It can be seen that the consumption of 1 volume of oxygen must consume 2 volumes of hydrogen at the same time.

So in the volume of change b liters oxygen accounts for 1 3 and hydrogen accounts for 2 3 If the rest is hydrogen, then the original hydrogen volume is a - b + 2 3b = a - 1 3b liters.

Oxygen is 1 3b liters.

If the rest is oxygen.

Then the original hydrogen volume is 2 3b liters.

Oxygen is a - b + 1 3b = a - 2 3b liters.

If there is nothing left.

Then hydrogen is 2 3b and oxygen is 1 3b

2.When the container is filled, the mass of organic vapor is more than air, and the water is 500g more than air, which can be calculated from the known molar mass of air of 29g mol and the molar volume of gas.

If the density of organic vapor is x, the air is a, and the water is b = 1000g l, then.

The ratio of x-a to b-a is equal to.

It can be counted as x

The relative molecular mass of this organic vapor is.

x/a)*29=

2h2+o2=2h2o，△v=3

x..a-x...b

x=2b/3(h2),o2:a-2b/3

2) Set the bottle volume to vl, because 1l of water is 1000g, so 1000v-29v, remove v=

Then using the same method, the relative molecular mass of the organism is x, xv so x=

When the hydrogen volume is 2b 3, the oxygen volume is a-2b 3, the oxygen volume is b 3, and the hydrogen volume is a-b 3

Let the bottle mass be x

Obtain x and then find (the value of b

That is, what is sought.

2h2+o2=2h2o

1. Hydrogen overdose:

then oxygen is b 3 and hydrogen is a 2b 3

2. Oxygen overload:

then hydrogen is 2b 3 and oxygen is a 2b 3.

Let its molecular weight be x, then (x 29) v

v(ml)＝

Al3+ has 3 positive charges, Mg2+ has 2 positive charges, the whole solution is electrically neutral, and the ratio of the amount of Al3+ and Mg2+ (ions) is 2:3 to infer that the positive charges shared by these two ions are equal. The sulfate ions in the 2molSO4 ion mixture have a negative charge of 4 mol, so half of the 2mol charge of the cation is carried by magnesium ions, so the magnesium sulfate is one mole, so the mass of magnesium sulfate is··· Do the math yourself!

Let the amount of Al3+ be 2a, then the amount of Mg2+ is 3a.

Because the solution is electrically neutral.

So: 2a 3+3a 2=2mol 2 solution: a=1 3mol

So: m(mg2+)=3 a 24g mol=24g

Let mg x mol, al y mol, then there is 24x+27y=mg(oh)2 x mol when the precipitation is maximum, and al(oh)3 y mol is generated, then there is 2x + 3y = 1

The maximum value of x= y= precipitate is mol

Magnesium mass fraction in total = (24 100 =

At the maximum precipitate, the volume is twice that of dissolution, then NaOH is also 400 ml of precipitate is Mg(OH)2, Al(OH)3Let mg be xgThen Al is (the amount of OH in the precipitate is 1mol L*400ml=(x 24)*2+[(.)]

Solve x, and the rest should be counted by yourself.

The first question is to read the picture directly, and you can get 60ml

The second question is also to read the map, the total gas is 60ml, half is 30ml, the corresponding time is 1 minute, the third question is still to read the map, reaction rate = gas release rate = tangent slope of the curve (in fact, the most fundamental is equal to the derivative value of this curve at the point after derivation, I don't know if you learn the derivative, so you don't need this), you can see that the tangent slope d>c>b>a, so the reaction rate is sorted from fast to slow is d c b a

Fourth, it should be that the hydrogen peroxide has completely decomposed.