Find answers to math lessons!! Rushing to solve math problems!!

1.Because OD and CE, OC and ED are parallel to each other, OCED is first and foremost a parallelogram.

And because ABCD is rectangular, so od=oc, then oced is a diamond.

2.Connecting the OE, we can see that OE=BC=8, DC=6, so OCED area=6x8 2=24

The answer is like a cover: the old filial hand is cautious.

What are the requirements for the question, and is it simplified?

The solution is as follows: grasp the seepage diagram of the god worship section of the blind spine.

Hope that helps.

Solution: 1. Because the first squadron started 2 hours earlier than the second squadron by 4 2 kilometers, and the second squadron traveled more (12-4) kilometers per hour than the first squadron, it is possible to find the time for the second squadron to catch up with the first squadron.

Solution: 4 2 (12-4).

1 (hour) Answer: The second squadron can catch up with the first squadron in 1 hour.

2. Set up to burn it out according to the plan, and burn it for x days.

1500(x-1)=1000(x+1)

3x-3=2x+2

x=5 needs to be burned [(5-1) 1500] 5=1200, so burn 1200 kg per day.

3. Solution: Each exercise book is more expensive than each pencil

Yuan) 8 exercise books are more expensive than 8 pencils:

Yuan) the price of each pencil:

meta) can also be solved with equations:

If a pencil is $x, then an exercise book is $.

8x+5×=

64x+19-25x=

39x=x=A: Each pencil element.

4. Solution: The number of trucks:

Number of 12 (Units) Passenger Cars:

9 (units) A: 12 trucks and 9 buses are available.

5. Solution: Number of days that have been repaired:

12 (days) the total length of the highway:

10800 (m).

A: The total length of this road is 10,800 meters.

6. Solution: 12 cartons are equivalent to the number of wooden boxes

2 (12 3) = 2 4 8 (pcs).

A double number of shoes in a wooden box:

1800 (8+4)=18000 12=150 (pairs) The number of pairs of shoes in a carton:

150 2 3 = 100 (double).

A: Each carton can hold 100 pairs of shoes, and each wooden box can hold 150 pairs of shoes.

7. Solution: The number of days when the cement runs out:

120 (30 2-40) = 120 20 = 6 (days) Total number of bags of cement:

30 6 = 180 (bag).

Total number of bags of sand:

180 2 = 360 (bag).

A: 180 bags of cement and 360 bags of sand were brought in.

8. Solution: The price of each teacup:

90 (4 5+10) = 3 (yuan).

Price per thermos:

3 4 = 12 (yuan).

A: 12 yuan per thermos flask, 3 yuan per teacup.

9、。Solution: The first additive:

The second plus:

A: The two additions are 52 and 520, respectively.

The first problem is actually accumulation, a number to the third power is -27, and the number is -3

The second question is based on the answer to the first question, -27 is first opened to the third power, then it is -3, and then the square is 9

The first question wants to tell you that the calculation of the power of the singular number does not change the nature of positive and negative numbers, and the answer to the first question is -3, so in the second question, the third power of a number is actually to the third power of this number, and the third power of -27 is equal to -3, because the first question tells us that the power of -3 is -27, and then the square calculation is performed after -3, and the square of -3 is 9.

(1)-3

2) From the first question, it can be seen that -27 = (-3), so the formula of (2) can be expressed as [(-3) ] 2 3, and the simplification obtains: (-3) gives the original formula = 9

It should be very detailed.,The 2 3 in the analysis is the square.,Don't get me wrong.。

The answer to the first question is -3, and the answer to the second question is:

If x=1, y=1, then f(f1) f1=f2=0, and because, when 0 lets x=3 2, y=1 2, then f(3 2f1 2) f1 2=f2=0, f1 2 cannot be equal to 0, so f(3 2f1 2)=0=f(f1)The slag is simply 3 2f1 2 = f1 = 2, so f1 2 = 4 3;

Let x=1 and y=2, then f(3)=f(2) f(f2)=0;So f1 kairan 2 + f3 = 4 3 + 0 = 4 3

I'm a little dizzy with my grandson's pants, I don't know if that's the case.

1) Let team A's time to complete the task be t1, so t1=4 (x+y). Team B's time is t2=1 x+1 y=(x+y) xy

2) t1-t2=(4xy-x 2-2xy-y 2) (xy(x+y))=x-y) 2 (xy(x+y)), because x>0,y>0,x≠y, so xy(x+y)>0, -x-y) 2>0, the result is t1-t2<0. The conclusion is that Team A finishes first.

Solution: (1) The time required for Team A to complete the task is 2 (12x+12y) = 4x+y

The time required for team B to complete the task is 1x+1y= x+yxy, so the time required for teams A and B to complete the task is 4x+y days, x+yxy days (2) t1-t2=4x+y-x+yxy= 4xy-(x+y)2xy? (x+y)=-x-y)2xy(x+y)

x≠y, x 0, y 0, (x-y)2 0, xy(x+y) 0 -(x-y)2 0, x-y)2xy(x+y) 0, i.e. t1-t2 0, t1 t2

Team A completes the mission first

Voydge's is very good.,Why aren't you satisfied?。

1600 words.

800*95%=760 trees.

Science and technology 2400

Education 50%.

The original plan was to produce x units this month x * 60% + 300 = 4800x = 7500 units.

It is obtained from the inner sum of the triangle equal to 180°, a=180°- abc- acb, and abc=180°- ebc, acb=180°- bcd, so a=180°-(180°- ebc)-(180°- bcd)= ebc+ bcd-180°

Again, the sum of triangles is equal to 180°, o=180°- obc- ocb, obc+ ocb=180°- o

EBC=2 OBC and BCD=2 OCB were obtained by dividing EBC and BCD=2 OCB respectively by Bo and CO, respectively, and substituting A= EBC+ BCD-180° were obtained.

a=2 obc+2 ocb-180°=2( obc+ ocb)-180°, and then substitute obc+ ocb=180°-o into the above equation.

a=2（180°-∠o）-180°

a=180°-2∠o.

Then the relationship between A and O is.

a=180°-2∠o