If Tana Cota 10 3,a 4, 2 , then the value of sin 2a 4 is

tana = the reciprocal of cota, so let tana be x, x+1 x=10 3, a quadratic equation, it is easier to solve, x is equal to 3 or 1 3, there is because a ( 4, 2), so, x is equal to 3

sina cosa = tana = 3, sina squared plus cosa squared equals 1, cosa equals sqrt10, sina equals (sqrt10) 3, sin(2a+ 4), sin( +=sin cos +sin cos 2 =2sin cos ,cos 2 = (cos)2-(sin )2=2*(cos)2-1=1-2*(sin )2, answer d

Select D for analysis.

tana+1 tana=10 3 tana=3 or 1 3a belongs to (4/4) tana>1 tana=3sin2a=2tana (1+tan 2a) (universal formula) sina2a=3 5 cos2a=4 5

sin (2a + 4 ths) = 7 root number 2 10

tana+1 tana=10 3 tana=3 or 1 3a belongs to (4/4) tana=3

sin2a=2tana (1+tan 2a) (universal formula) sina2a=3 5 cos2a=4 5

sin (2a + 4 ths) = 7 root number 2 10

dtana+1 tana=10 3 tana=3 or 1 34ths) tana>1 tana=3sin2a=2tana (1+tan 2a)sina2a=3 5 cos2a=4 5

sin (2a + 4 ths) = 7 root number 2 10

,tana)^2+10tana/3+1=(tana+3)(tana+1/3)=0

tana = -3 or -1 3

3π/4＜a＜π,tana>-1,tana=-1/3

Denominator = - 2cosa

Molecule = 5(1-cosa) 2 + 4sina + 11 (1 + cosa) 2-8 = 3 cosa + 4sina

Original formula = (3cosa+4sina) (2cosa)=-2(3+4tana) 2,2, known 3 4 a, tana+cota= -10 3?

1. Find the value of tana.

2, find 5 times (sina 2) squared + 8sina 2cosa 2 + 11 multiplied (cosa 2) squared - 8

More 2 times sin (a-2).

sin square liquid ridge shed + cos square = 1, so trouble, (sina + cosa) 2 = 1 + 2 sinacosa = 1-3 5 = 2 5, so, open square.

Others need to be transformed. Wild digging.

There is no need to ask for liquid f-sa cosa, sina

4cos²a+3sin²a

4cos²a+3sin²a)/1

4cos noisy rush a+3sin a) (sin a+cos a) numerator denominator is divided by cos a

4+3tan²a)/(tan²a+1)

If you agree with me, please click on the "answer for satisfaction" in the lower left round corner, and wish you progress in your studies!

,tana)^2+10tana/3+1=(tana+3)(tana+1/3)=0

tana = -3 or -1 3

Type Dou Regret 3 Pin Vertical 4 A, tana>-1, tana = -1 3, denominator = - 2cosa

Molecule = 5(1-cosa) 2 + 4sina + 11 (1 + cosa) 2-8 = 3 cosa + 4sina

Original formula = (3cosa+4sina) Bu Zheng (- 2cosa) = -2(3+4tana) 2

tana+cota=-10/3

3tan^2a+10tana+3=0

3tana+1)(1+3tana)=0

tana1=-1/3,tana2=-3

Because 3 4, tana = -1 3

5SIN 2A 2+8SINA 2*COSA 2+11COS 2A Kaiqiao 2-8) Neno Spike 2SIN (A-4).

5(1-cosa)/2+4sina+11(1+cosa)/2-8]/(sina-cosa)

3cosa+4sina)/(sina-cosa)(3+4tana)/(tana-1)

3-4 3) Spine key (-1 3-1).

1, tana + cota = tana + (1 tana) = 3 10 = (3 -1 3) (you can see it at a glance).

tana = 3 or tana = -1 3

And 3 4 a, 1 write out your process, point it out and pull it,

tan(π/4 +αcos2α ]2cos²(π4 -

tan(π/4 +αcos2α ]1 + cos(π/2 - 2α)

tan(π/4 +αcos2α ]1 + sin2α )

tan(π/4 +αcos²α sin²α)sin²α+cos²α 2sinαcosα)

tan(π/4 +αcosα+sinα)(cosα -sinα) sinα+cosα)²

tan(π/4 +αcosα -sinα) cosα+sinα)

1+tan ) 1 - tan ) 1 - tan ) 1+tan ) The numerator and denominator are the same as those obtained by dividing by cos

It is known that tan( 4+a)=1 2 knows.

Satisfactory tan 4=1 so (1+tana) (1-tana)=1 2 2+2tana=1-tana tana=-1 3 sina cosa=tana=-1 3 cosa=-3sina then cos a=9sin a because sin a+cos a=1 so sin a=1 10, cos a=9 1....

2cos²(π4-a)

1+cos(π/2-2a)

1+sin2a

sin²a+cos²a+sinacosa

sina+cosa)²

cos2acos²a-sin²a

cosa+sina)(cosa-sina)tan（π/4+a）.cos2a /[2cos²（π4-a)]tan(π/4+a)(cosa+sina)(cosa-sina)/(cosa+sina)²

tan( 4+a)(cosa-sina) (cosa+sina)(1+tana) (1-tana)* 1-tana) (1+tana) (the front tangential two corners are sumed, and the back is divided by cosa at the same time).