How does the acceleration of a trolley that starts at rated power change?

The trolley started at the rated power, the traction force does not change, the drag does not change, and the acceleration is equal to the traction force minus the resistance divided by the mass, the acceleration does not change.

As the velocity increases, the acceleration decreases gradually until it reaches zero.

Calculated based on p=fv,When the car starts at the rated power, the power p is unchanged, the velocity v is increasing, the traction force f is decreasing, the resistance f of the car is generally unchanged, the resultant force f-f of the car is decreasing, the acceleration a=(f-f) m is decreasing, but the velocity is increasing, it is a variable acceleration linear motion, and it cannot be solved directly by Newton's law of motion.

Analysis of automotive engine power test results.

For steady-state dynamometer, it can also be called load dynamometer, which means that when the throttle valve of the engine is opened to a certain extent, the parameters must remain unchanged and stable under the condition of maintaining a certain speed, and the power of the engine must be measured by the simulated load of the engine in the measurement of engine function. For steady-state dynamotry, there is a certain relationship between the effective power of the engine and the torque and speed. There are specific formulas to calculate.

For dynamic dynamometer is to turn all the moving parts of the engine as a centerline around the crankshaft, which is a relatively simple rotary body, because there is no external load of the engine, because at idle or low speed, the large throttle will accelerate to a certain high-speed running speed, so the engine must overcome various mechanical obstacles.

The remaining torque is also the effective torque to accelerate the engine. By measuring the angular acceleration of the engine to measure the time used by the engine at low and high speeds, the power emitted by the engine can also be calculated.

The speed of the car when the car starts from a standstill and accelerates uniformly with acceleration a, then the speed of the car when the car just reaches the rated power.

Dear, hello, I am very honored to be able to answer for you, the car starts from a standstill that is to accelerate the acceleration of the movement of the rubber loss a, then when the car just reaches the rated power, the speed of the car: has not reached the maximum value [analysis] When the car just reaches the rated power, it also has acceleration, by f a f = ma and p = fv, after f gradually decreases, the acceleration a also gradually decreases, the speed continues to increase until the acceleration is zero, the speed reaches the maximum, so b is correct. Idea Analysis:

When the car just reaches the rated power, it also has acceleration, by F - F = Ma and P = FV, after which F gradually decreases beam by beam, acceleration a also gradually decreases, and the speed continues to increase, until the acceleration is zero, the speed reaches the maximum.

Summary. Extended information: to calculate the maximum power of the DC motor, first of all, you have to determine the no-load performance of your motor, such as the no-load speed, and secondly, you have to calculate the slope of your motor, and the slope is equal to the dynamic resistance of the DC motor divided by ct*ce, so you only need to get the torque coefficient and potential coefficient of the motor, you calculate the maximum power of the motor!

When the car passes at a speed of 30 km h and the maximum climb is 25%, the maximum power output of the drive motor is.

Dear, I'm glad to answer for you! If the maximum climb is 25%, the maximum climb height is 25% 30km h=. According to the relationship between power and height, the maximum power = height weight and transportation, so the maximum power = vehicle weight vehicle weight kw.

Extended information: the maximum power calculation of the DC motor, first of all, you have to determine the no-load performance of your motor type hand Tongbutan, such as the no-load speed, and secondly, you have to calculate the slope of your motor, and the slope is equal to the dynamic resistance of the DC motor divided by CT*CE, so as long as you get the torque coefficient and potential coefficient of the motor, you can calculate the maximum potato power of the motor!

The water in this is not very deep, but it is more useless to make it clear from the Internet.

Let's start with the rated power, the rated power (maximum power) starts, and the acceleration movement is constantly decreasing. Finally, the acceleration is zero, reaching the maximum velocity. Notice that the acceleration tends to infinity at startup.

In addition, the uniform acceleration start, that is, the start with a fixed acceleration, when p=(ma f)v reaches the rated power, the acceleration movement with reduced acceleration is done, and finally the maximum speed is reached.

The maximum speed is the same in both cases. Of course, starting from a standstill and driving over the same displacement will result in a short start-up time at rated power.

Is there anything else I don't understand that I can add.

The power is constant and the speed is gradually increased.

Because p=vf

So the pulling force gradually decreases.

Because a=f m

Therefore, the acceleration of the nightshade gradually decreases.

At this time, the car changes and trembles, accelerates in a straight line (and the acceleration decreases), and when the tensile force decreases to equal to the resistance.

It begins to move in a straight line at a uniform speed.

Hope it helps.

When the car just reaches the rated power, it also destroys the acceleration, by f-f=ma and p=fv, after which f gradually decreases, the acceleration travel a also gradually decreases, the speed continues to increase and the number of dismantling increases, until the acceleration is zero, the speed reaches the maximum, so the acd is wrong, b is correct

Therefore, choose B

Answer B When the car has just reached the fixed power of the forehead, it also has acceleration, which is determined by f f ma and p fv, and then f gradually decreases, and the acceleration a also gradually decreases, and the speed continues to increase until the acceleration is zero, and the velocity reaches the maximum, so b is correct

Idea analysis: when the car just reaches the rated power, it also has acceleration, by f f ma and p fv, after f gradually decreases, acceleration a also gradually decreases, the speed continues to increase, until the acceleration is zero, the speed reaches the maximum, test question comments: this question examines the problem of locomotive starting, this question belongs to the start with constant acceleration, view the original post "cavity group".

Known: p=50kw=50000w t=10s

Find: w=? w=pt=50000w×10s=500000j=5×10⁵j

The work done by the engine is 5 10 J.