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I don't agree with what I said upstairs, p=ui is true, but there is one of the most primitive formulas that is p=i squared * r. So, as soon as your r is smaller, your i rises in a squared relationship. So, if the resistance is smaller, the more heat will be generated, but only if you have enough power to supply the resistor.
And the actual power of your resistor can't exceed the nominal power of the resistor. You can buy those metal encapsulated resistors, the power of those resistors can go up to 50W, and the resistors are also small, but if you use them at its rated power, its temperature can go to very high (I tried, it is about 80 to 100 degrees), and it will not burn out.
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Miniature thermistor platinum resistors are small and fast.
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It is difficult to heat up quickly if the resistance is small, according to p=u 2 r, it can be known that if you want to heat up quickly, you must add high voltage at both ends of the resistor, and the general heating resistance is high resistance.
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It is that the large resistance generates more heat, and the small resistance heats less, and the cold and hot resistance of the heating cable are different, and the hot resistance is larger.
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This wire is a thermistor source.
The resistance is very small at room temperature, and when the current is 220V as above, the current will be very large and immediately heated, and the resistance will increase rapidly. When the heat reaches a certain level, of course, the resistance will also be large to a certain extent, and the current will drop to a certain value. It will reach a stable state, which is 17 watts per meter.
Of course, this is the data at room temperature, if the wattage will increase in a lower temperature environment, and the wattage will become smaller when the insulation effect is good.
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Hehe, it's very simple. The smaller the resistance, the greater the power.
The basic formula for power is p=u*i
The voltage of the mains is 220V, which is basically fixed. The greater your resistor weight, the smaller the current and the smaller the corresponding power.
As for p=u2 r p=i2r, both formulas are its deformations according to Ohm's law!
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It's hard to say that you have a problem here, hehe, the fever is self-sufficient.
The resistance wire is outsourced at the time of the cable.
baidupvc, the temperature of the heat is not high, the path does not represent the zhi meter and there is no resistance, and the opposite of the path dao is the open circuit. The following questions are not easy to answer, my knowledge is shallow, I think in a certain resistance range is the resistance is small and the heat is large, but the resistance is small like copper wire, which is another story.
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Any wire has resistance, and your meter gear is too high, so it's best to use a x1 gear, and the resistance can generally be measured.
If the resistance is small, the current is strong, and the heat generation is large.
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1. Any conductor will have resistance, and the resistance of some conductors is very small, which is normal. The DAO measurement version shows no resistance. It's just that the gear selection of your measuring instrument is different, and the result is different.
2. According to Joule's law, electric heat is generated when any conductor passes through an electric current. This is the conductor heating.
3. Because the voltage is fixed at 220V, the smaller the visible resistance is according to Q=W=(U2 R)*t, the more the resistance heats up in a certain time.
Hope it helps.
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There is resistance, and the meter gear is too high. The resistance is small and the heat is more.
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The smaller the resistance, the more heat is generated, but at the same time, the current is also larger, and the current is too large to be a short circuit.
It tripped. And it's going to be dangerous.
To put it simply, the smaller the resistance under the current limit, the better. But the specific needs to be calculated and demonstrated, and they can't be messed around.
It is right to look at the size of p, the greater the power p, the faster the heating. Two formulas, the voltage does not change with the first is right, because i=u r, substituted into the second, is the first one.
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This depends on the resistance of the material, because the resistivity p of various substances is related to temperature, so the resistance of various conductors also changes with the change of temperature, the resistance of general metal conductors increases with the increase of temperature change, the resistance of a few alloys does not change with temperature, and the resistance of semiconductors increases with temperature change and decreases.
where 0 is 0; is the temperature coefficient of the resistance; The unit of temperature t is Celsius. The resistivity of semiconductors and insulators is different from that of metals, and they do not vary linearly with temperature.
When the temperature increases, their resistivity decreases dramatically. Exhibits a non-linear variation. The reciprocal 1 of resistivity is called conductivity and is denoted by .
It is also a parameter that describes the conductivity of a conductor, and its SI system of units (SI) is the Siemens meter (S m).
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Answer: c
The resistance of a metal conductor increases as the temperature increases.
There are many insulators that lose their insulation at high temperatures, but are still insulating below 100;
Semiconductors increase their conductivity with increasing temperature, and can be made into thermistors;
Superconductors are superconductive only when the temperature is close to minus 273 degrees Celsius.
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c Semiconductors.
Semiconductors generally have negative temperature characteristics.
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In fact, this should have different characteristics according to different types. However, for a separate topic, C should be chosen. Some of the topics are just that weird.
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